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Helga [31]
3 years ago
5

Select the most SPECIFIC name for this shape

Mathematics
2 answers:
bazaltina [42]3 years ago
4 0

Answer:

Rectangle

Step-by-step explanation:

lubasha [3.4K]3 years ago
3 0
Rectangle would be the most specific for it.
In square all sides need to be equal.
In parallelogram the angles need not be 90 which means rectangle is parallelogram but parallelogram is not a rectangle.
A rhombus is a quad with all sides having equal length.
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Very confusing problem
Ronch [10]

Answer:

b = 5

Step-by-step explanation:

if parallelogram is a rectangle, then the two diagonals has the same length

10/12 x(24/5 x b - 36/5) = 2/3 x (3b + 6)

4b - 6 = 2b + 4

2b = 10

b = 5

4 0
3 years ago
Find the surface area of the triangular prism.<br><br> 15.6 cm<br> 10 cm<br> 11 cm<br> 12 cm
dimulka [17.4K]

Answer:

533.6cm²

Step-by-step explanation:

Hello!

I'm here to answer your question!

<u>Area of each triangular base:</u>

\frac{1}{2}(12)(10)=60

<u />

<u>Area of the rectangular faces:</u>

12\times 11 =132

15.6\times 11=171.6

10\times 11=110

<u>Add to find the surface area:</u>

60+60+132+171.6+110=533.6

Thus, the surface area of the triangular prism is = 533.6 yd²

Hope this helps you!

Hugs from,

Josh

6 0
3 years ago
Read 2 more answers
7. The length of a rectangle is 3 centimeters less than twice its width. The perimeter of the rectangle is 48 cm. What are the d
irga5000 [103]
The answer is b

The perimeter of a rectangle is 2(l + w) so in this case, it is 2(15 + 9) and that is equal to 48. But so at c and d. So u need to multiply the width by 2 (9*2=18) and then you’ll see that 18-3=15. And therefore, the length is -5 and the width is 9
5 0
3 years ago
37. ABC has vertices A(0, 0) , B(0, 4) , and C(3, 0) . Write the equation for the line containing the altitude overline AR in st
Nutka1998 [239]

Answer:

3x - 4y = 0

Step-by-step explanation:

The triangle Δ ABC has vertices A(0,0), B(0,4) and C(3,0).

Therefore, the equation of the straight line BC in intercept form will be  

\frac{x}{3} + \frac{y}{4} = 1

⇒ 4x + 3y = 12

⇒ y = - \frac{4}{3}x + 4 .......... (1)

This is a equation in slope-intercept form and the slope is - \frac{4}{3}.

Now, the altitude AR is perpendicular to equation (1) and hence its slope will be \frac{3}{4}.

{Since, the product of slope of two mutually perpendicular straight line is always - 1}

Therefore, the equation of the altitude AR which passes through A(0,0) will be  

y = \frac{3}{4}x

⇒ 4y = 3x

⇒ 3x - 4y = 0 (Answer)

4 0
3 years ago
Heyyy, please answer :]
Yuliya22 [10]
The solution is “no real solution”
Because the slope is the same, so they are parallel.

Hope that help!! :-)
6 0
2 years ago
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