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Deffense [45]
2 years ago
12

The number of sit-ups that all tenth-grade girls can do in 5 minutes is normally distributed. beth surveyed 20 of her fellow int

ramural tennis players, all tenth-grade girls, and determined the mean number of sit-ups they could do. can she make an inference about the population mean for all tenth-grade girls based on the sample? no, because the sample size was not big enough. no, because she did not use a simple random sample. yes, because the sample size was big enough. yes, because she used a simple random sample.
Mathematics
2 answers:
Maksim231197 [3]2 years ago
8 0

Answer:

the correct answer is B.

Step-by-step explanation:

<em>~Hope this helps! :)</em>

Luda [366]2 years ago
5 0

The true statement is as follows "No because she did not use a simple random sample".

<h3>What is random sampling?</h3>

Random sampling is the method to choose the given samples of observation to make assumptions about the population.

It is given that

Population: All tenth-grade girls

Sample: 20 intramural tennis players

The 20 intramural tennis players cannot represent all tenth-grade girls.

This is so because the selection is biased here, and it could not be used to make inferences about the overall population. then she did not use a simple random sample.

Hence, the true statement is (b)

Read more about random sampling at:

brainly.com/question/1334729

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jolli1 [7]

Answer:

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Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
1.Show that the statement p: “If x is a real number such that x3 + 4x = 0, then x is 0” is true by
Genrish500 [490]

If x is a real number such that x3 + 4x = 0 then x is 0”.Let q: x is a real number such that x3 + 4x = 0 r: x is 0.i To show that statement p is true we assume that q is true and then show that r is true.Therefore let statement q be true.∴ x2 + 4x = 0 x x2 + 4 = 0⇒ x = 0 or x2+ 4 = 0However since x is real it is 0.Thus statement r is true.Therefore the given statement is true.ii To show statement p to be true by contradiction we assume that p is not true.Let x be a real number such that x3 + 4x = 0 and let x is not 0.Therefore x3 + 4x = 0 x x2+ 4 = 0 x = 0 or x2 + 4 = 0 x = 0 orx2 = – 4However x is real. Therefore x = 0 which is a contradiction since we have assumed that x is not 0.Thus the given statement p is true.iii To prove statement p to be true by contrapositive method we assume that r is false and prove that q must be false.Here r is false implies that it is required to consider the negation of statement r.This obtains the following statement.∼r: x is not 0.It can be seen that x2 + 4 will always be positive.x ≠ 0 implies that the product of any positive real number with x is not zero.Let us consider the product of x with x2 + 4.∴ x x2 + 4 ≠ 0⇒ x3 + 4x ≠ 0This shows that statement q is not true.Thus it has been proved that∼r ⇒∼qTherefore the given statement p is true.

8 0
3 years ago
You roll a six sided die how likely is it that you roll a number greater than or equal to 1
Grace [21]

Answer:

6/6

Step-by-step explanation:

3 0
3 years ago
How do i solve this? (1/3x-11)^(1/2)=5
photoshop1234 [79]
(\frac{1}{3} x-11)^{ \frac{1}{2} }=5\\ ((\frac{1}{3} x-11)^{ \frac{1}{2} })^{2}=(5)^{2}\\ \frac{1}{3} x-11=25\\ \frac{1}{3} x=36\\x=108
4 0
3 years ago
Read 2 more answers
a box with a square base and open top must have a volume of 70304 c m 3 cm3 . we wish to find the dimensions of the box that min
Dmitriy789 [7]

The box should have base 52 cm by 52 cm and height 26 cm.

What is volume?

A three-dimensional space's occupied volume is measured. It is frequently expressed as a numerical value using SI-derived units, other imperial units, or US customary units. Volume definition and length definition are connected.

The Volume of a box with a square base x by x cm and height h cm is

V = x^2h

Since the surface area directly affects the amount of material used, we can reduce the amount of material by reducing the surface area.

The surface area of the box described is  A = x^2 + 4xh

We need A as a function of x alone, so we'll use the fact that

V = x^2h= 70304 cm^3

⇒ h = \frac{70304}{x^2}

So, the area becomes,

A = x^2+4x(\frac{70304}{x^2})\\ A = x^2 + \frac{281216}{x}

We want to minimize A, so

A' = 2x - \frac{281216}{x^2} =0\\\frac{2x^3-281216}{x^2}=0\\ {2x^3-281216} = 0\\x^3 - 140608=0\\x^3 = 140608\\x = 52

The second derivative test verifies that A has a minimum at this critical number:

A'' = 2+\frac{562432}{x^3}  which is positive at x = 52.

Now,

h = \frac{70304}{x^2}= \frac{70304}{(52)^2}=26

Hence, The box should have base 52 cm by 52 cm and height 26 cm.

To know more about volume, click on the link

brainly.com/question/463363

#SPJ4

8 0
1 year ago
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