8y^3+316
divide both sides by 4 (smallest divisable number) just say you tried to factor 2 and 3 and they weren't whole numbers and then you tried 4 and gave you the answer :)
4(2y^3+79)
Me too , please help I'm taking a Geometry common assessment
Answer:
x-6 + 2x-8 = 10
Step-by-step explanation:
ST + TU = SU
x-6 + 2x-8 = 10
Combine like terms
3x - 14 = 10
Add 14 to each side
3x-14+14 = 10+14
3x = 24
To start, you can use clue 2 because there is only one variable in it.
Solve for the value of the circle, by dividing both sides by 3.
Then you can plug that value into clue 1 to solve for the diamond.
Once you find the value for the diamond, you can plug both values, the diamond and the circle, into clue 3, to solve for the triangle.
Answer:
The two numbers are 19 and 84