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satela [25.4K]
3 years ago
12

Please help I need to know now :(

Mathematics
2 answers:
babunello [35]3 years ago
5 0

Answer:

\frac{6x*x^{3}}{y^{2}}\\\\

Step-by-step explanation:

a^{-m}=\frac{1}{a^{m}}\\\\\frac{1}{a^{-m}}=a^{m}\\\\a^{m}*a^{n}=a^{m+n}\\\\\\\frac{6xy^{-2}}{x^{-3}}=\frac{6*x*x^{3}}{y^{2}}\\\\=\frac{6x^{(1+3)}}{y^{2}}\\\\=\frac{6x^{4}}{y^{2}}

Ainat [17]3 years ago
3 0
I think it’s y^2.
...
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krek1111 [17]

Step-by-step explanation:

Area of circular pond=22/7×14×14

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>2</em><em>2</em><em>/</em><em>7</em><em>×</em><em>1</em><em>9</em><em>6</em>

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3 years ago
(6z²+z-1)(9z-5) polynomial equation
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8 0
3 years ago
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Travka [436]

Answer: (x-2) (x^2 + 2x + 4)

Step-by-step explanation:

x^3 - 8

x^3 - 2^3

(x-2) * (x^2+x * 2 + 2^2)

(x-2) (x^2 + 2x + 4)

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4 years ago
What is the cross-sectional area of a wire if its outside diameter is 0.0625 inch?
Leno4ka [110]

Given that the diameter: d= 0.0625 inch.

So, radius of the wire : r = \frac{0.0625}{2} = 0.03125 inch

Now the formula to find the cross-sectional area of wire ( circle) is:

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Hence, cross-sectional area of a wire is 0.00307 square inches.

Hope this helps you!

5 0
3 years ago
Read 2 more answers
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