In order to be differentiable everywhere, 
must first be continuous everywhere, which means the limits from either side as 
must be the same and equal to 
. By definition, 
, and
so we need to have 
.
For to be differentiable at 
, the derivative needs to be continuous at , i.e.
We then need to have
Then
Answer:
I think it is 3 + (6 + 2) or 11
Step-by-step explanation:
You first find 3 pens and 6 markers. Then you find 2 more markers at the bottom of your locker. The common answer I think would be 3 + (6 + 2) or If your teacher wants a whole answer, 11.
I hope this helped
I am sorry if I got it incorrect
Theres about 800 different combinations, i'm not sure though, i'm sorry if i'm wrong
For 70 people i would say ab 445
