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lbvjy [14]
3 years ago
14

Can u plz show work?Only need 84

Mathematics
1 answer:
Sonbull [250]3 years ago
6 0

Answer:

Step-by-step explanation:

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dlinn [17]
\dfrac{2}{3}t-3\leq1|\cdot3\\
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\boxed{t\in(-\infty,6]\cup(12,\infty)}

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For any function, we call x the ____________ value and y is the _______________ value.
Fantom [35]
Numerator and denominator
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Mindy makes an annual salary of $24,590. What is the maximum monthly rent she could afford to pay?
Otrada [13]
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3 years ago
Read 2 more answers
Find the distance between each pair of points<br> 8) (2, 6), (5, 10)<br> 9) (-3,-10), (-3,5)
Lapatulllka [165]

Answer:

8) answer=5 9)answer=15

Step-by-step explanation:

all you have to do is replace in the following formula

\sqrt{(x2-x1)^{2}+ (y2-y1)^{2}} =d

Where

X1: is the first number of the first point

Y1: is the second number of the first point

X2:  is the first number of the second point

Y2: is the second number of the second point

you replace in the formula and solve

I attach solution

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3 years ago
Fill in the blank with a constant, so that the resulting expression can be factored as the product of two linear expressions: 2a
Vitek1552 [10]

Answer:

2ab - 6a + 5b - 15

Step-by-step explanation:

Given

2ab - 6a + 5b + \_

Required

Fill in the gap to produce the product of linear expressions

2ab - 6a + 5b + \_

Split to 2

(2ab - 6a) + (5b + \_)

Factorize the first bracket

2a(b - 3) + (5b + \_)

Represent the _ with X

2a(b - 3) + (5b + X)

Factorize the second bracket

2a(b - 3) + 5(b + \frac{X}{5})

To result in a linear expression, then the following condition must be satisfied;

b - 3 = b + \frac{X}{5}

Subtract b from both sides

b - b- 3 = b - b+ \frac{X}{5}

- 3 = \frac{X}{5}

Multiply both sides by 5

- 3 * 5 = \frac{X}{5} * 5

X = -15

Substitute -15 for X in 2a(b - 3) + 5(b + \frac{X}{5})

2a(b - 3) + 5(b + \frac{-15}{5})

2a(b - 3) + 5(b - \frac{15}{5})

2a(b - 3) + 5(b - 3)

(2a + 5)(b - 3)

The two linear expressions are (2a+ 5) and (b - 3)

Their product will result in 2ab - 6a + 5b - 15

<em>Hence, the constant is -15</em>

3 0
3 years ago
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