Question

Triangle XYZ has vertices X(–1, –3), Y(0, 0), and Z(1, –3). Malik rotated the triangle 90° clockwise about the origin. What is the correct set of image points for triangle X’Y’Z’? X’(3, –1), Y’(0, 0), Z’(3, 1) X’(1, 3), Y’(0, 0), Z’(–1, 3) X’(1, –3),Y’(0, 0), Z’(–1, –3) X’(–3, 1), Y’(0, 0), Z’(–3, –1)

Answer 1

Answer:

Option D.

Step-by-step explanation:

It is given that triangle XYZ has vertices X(–1, –3), Y(0, 0), and Z(1, –3).

Malik rotated the triangle 90° clockwise about the origin. So, rule of rotation is

$(x,y)\to (y,-x)$

Now,

$X(-1,-3)\to X'(-3,-(-1))=X'(-3,1)$

$Y(0,0)\to Y'(0,0)$

$Z(1,-3)\to Z'(-3,-(1))=Z'(-3,-1)$

The image points are X’(–3, 1), Y’(0, 0), Z’(–3, –1).

Therefore, the correct option is D.