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scoundrel [369]
3 years ago
6

A local bank in town offers two types of savings plan with different interest rates to customers. Plan A offers an annual intere

st rate of 0.25% (0.0025) of the amount deposited. Plan B offers an annual interest of 0.2% of the amount deposited in the current year and 0.1% of the amount deposited two years back. Plan B will give 0.3% only for the first year of deposit. EXCEL Based on a retirement research article stated in a magazine, a minimum sum of $1 000 000 is required for one to retire comfortably. After reading the article, Ah Seng decides to deposit his $100 000 into the bank this year. Which plan should Ah Seng choose so that he is able to hit the $1 000 000 as quickly as possible without taking out his deposit at any point in time?
Mathematics
1 answer:
scoray [572]3 years ago
6 0
Assuming he had not dealt with the bank offering plan B before, he has nothing deposited two years back.  Hence plan B only gives him only 0.2% annual interest for his deposit.
Plan A gives 0.25% for his deposit all the time.
So plan A is more advantageous.

For durations, 
To reach $1,000,000 from $100,000, the money needs to grow 10 fold, or
(1+i)^n=10
n=log(10)/log(1+i).

So for plan A:
n=log(10)/log(1.0025)=922.18 years, while for

plan B
n=log(10)/log(1.0020)=1152.44 years.
 
Hope the bank(s) still exist at that time.
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Mariulka [41]

Answer:

i) Since P(2), P(-1) and P(½) gives 0, then it's true that 2,-1 and 1⁄2 are the zeroes of the cubic polynomial.

ii) - the sum of the zeros and the corresponding coefficients are the same

-the Sum of the products of roots where 2 are taken at the same time is same as the corresponding coefficient.

-the product of the zeros of the polynomial is same as the corresponding coefficient

Step-by-step explanation:

We are given the cubic polynomial;

p(x) = 2x³ - 3x² - 3x + 2

For us to verify that 2,-1 and 1⁄2 are the zeroes of the cubic polynomial, we will plug them into the equation and they must give a value of zero.

Thus;

P(2) = 2(2)³ - 3(2)² - 3(2) + 2 = 16 - 12 - 6 + 2 = 0

P(-1) = 2(-1)³ - 3(-1)² - 3(-1) + 2 = -2 - 3 + 3 + 2 = 0

P(½) = 2(½)³ - 3(½)² - 3(½) + 2 = ¼ - ¾ - 3/2 + 2 = -½ + ½ = 0

Since, P(2), P(-1) and P(½) gives 0,then it's true that 2,-1 and 1⁄2 are the zeroes of the cubic polynomial.

Now, let's verify the relationship between the zeros and the coefficients.

Let the zeros be as follows;

α = 2

β = -1

γ = ½

The coefficients are;

a = 2

b = -3

c = -3

d = 2

So, the relationships are;

α + β + γ = -b/a

αβ + βγ + γα = c/a

αβγ = -d/a

Thus,

First relationship α + β + γ = -b/a gives;

2 - 1 + ½ = -(-3/2)

1½ = 3/2

3/2 = 3/2

LHS = RHS; So, the sum of the zeros and the coefficients are the same

For the second relationship, αβ + βγ + γα = c/a it gives;

2(-1) + (-1)(½) + (½)(2) = -3/2

-2 - 1½ + 1 = -3/2

-1½ - 1½ = -3/2

-3/2 = - 3/2

LHS = RHS, so the Sum of the products of roots where 2 are taken at the same time is same as the coefficient

For the third relationship, αβγ = -d/a gives;

2 * -1 * ½ = -2/2

-1 = - 1

LHS = RHS, so the product of the zeros(roots) is same as the corresponding coefficient

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Answer:

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Step-by-step explanation:

The problem statement tells you the independent variable w represents weeks that have passed. "Domain" refers to values the independent variable may have, so choices A or B make no sense here.

Time is measured continuously, and fractions of a week are possible. So, the domain could be <em>non-negative real numbers</em>. However, the answer choice D is "<em>all</em> real numbers", which includes negative numbers for which the function makes no sense.

The domain "all whole numbers" includes non-negative integers. It is reasonable to restrict the domain to non-negative integer numbers of weeks, so answer choice C is the best option.

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Answer:

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Table values:

x                  y

0                  9

2                  12

4                   15

6                   18

-6                  0

Now, plot these points (0,9), (2, 12), (4, 15) , (6, 18) and (-6, 0) on the co-ordinate planer, to graph the the line.

You can see the graph of the given equation as shown below.                  

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