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3 years ago

What pattern do you see in the powers of 4?

2 answers:

8 0

All of them are even numbers. You will not find a power of 4 that is an odd number. Also, all of the numbers have a 4 or a 6 or both. For example,
4^3= 64

4^8= <span>65536

I hope this helps:)</span>

Kay [80]3 years ago

3 0

They are all EVEN numbers

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How many times larger then 2x10² is 2x10⁸

Brrunno [24]

Answer:

1,000,000 times larger

Step-by-step explanation:

2 x $10^{8}$ = 200,000,000

2 x $10^{2}$ = 200

200,000,000 divided by 200 is 1,000,000

It can also be solved by subtracting the exponents from 10. Then dividing the two number being put the scientific notation.

$10^{8} - 10^{2}$ = $10^{6$

2 ÷ 2 = 1

Now solve:

1 x $10^{6$ = 1,000,000

3 0

2 years ago

Which point gives the vertex of ƒ(x) = –x2 + 4x – 3?

Dmitriy789 [7]

Answer:

The vertex is (2,1)

Step-by-step explanation:

ƒ(x) = –x^2 + 4x – 3

Factor out the negative

= -(x^2 -4x+3)

Factor

What 2 numbers multiply to +3 and add to -4

-3*-1 = 3

-3+-1 = -4

f(x) = -( x-3)(x-1)

Find the zeros

0 = -( x-3)(x-1)

0 = x-3 0 = x-1

x=3 x=1

The x value of the vertex is 1/2 way between the two zeros

(3+1)/2 = 4/2 =2

To find the y value, substitute x=2 in

f(2) = -( 2-3)(2-1)

=-(-1)(1) = 1

The vertex is (2,1)

4 0

2 years ago

There are 30 students in Mrs. Woodward’s class, and 1/5 of the class has their own cell phone. Of this group of students, 1/2 of

olga_2 [115]

Answer:

3 students

Step-by-step explanation:

There are 30 students in Mrs. Woodward’s class.

$\dfrac{1}{5}$ of the class has their own cell phone, so

$\dfrac{1}{5}\cdot 30=\dfrac{1}{5}\cdot \dfrac{30}{1}=6$

students have their own cell phones.

$\dfrac{1}{2}$ of those 6 students are allowed to use social media. So,

$\dfrac{1}{2}\cdot 6=\dfrac{1}{2}\cdot \dfrac{6}{1}=3$

students are allowed to use social media.

3 0

2 years ago

Amy jogs 1/3 of a mile in 1/15 of an hour, while john takes 1/30 of an hour to jog 1/5 of a mile. If they continue at this rate,

jolli1 [7]

Step-by-step explanation:

Given that,

Amy jogs 1/3 of a mile in 1/15 of an hour and john takes 1/30 of an hour to jog 1/5 of a mile.

Speed of Amy,

$v_1=\dfrac{\dfrac{1}{3}\ miles }{\dfrac{1}{15}\ h}=5\ mph$

Speed of John,

$v_2=\dfrac{\dfrac{1}{5}\ miles }{\dfrac{1}{30}\ h}=6\ mph$

John will jog farther in one hour as he is moving with faster speed. The speed of John is 1 mph more than Amy.

6 0

3 years ago

Given ASTU and ADEF, what is mZU?

salantis [7]

Answer:

Maybe the same as the angle of F (46)

Step-by-step explanation:

If you see the two shapes are the same. but different size. so therfore the angles are same.

3 0

2 years ago