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Katarina [22]
3 years ago
13

Two dice are thrown simultaneously. Given that sum of the numbers is NOT more than 5, what is the probability that sum is more t

han 3?
Mathematics
1 answer:
defon3 years ago
3 0
A method to know the probability is to list down all of the possible combinations that would present an outcome of not more than 5. This is listed below:

1 + 4
4 + 1
2 + 3
3 + 2
1 + 1
2 + 2
1 + 2
2 + 1
1 + 3
3 + 1

There are 10 possible outcomes. But among these, the only ones that can have a sum more than 3 are:

1 + 4
4 + 1
2 + 3
<span>3 + 2
</span>2 <span>+ 2
</span>1 + 3
3 + 1

There are only 7 possible outcomes that meet both requirements. Given that there are 7 outcomes within the total of 10, the probability would be 7/10, or 0.7.

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Express your answer exactly
adoni [48]

Answer:

cos(Θ) = 84/85

Step-by-step explanation:

See the attachment.

Sine is opposite divided by hypotenuse. Here, the "opposite" side is -13 and the hypotenuse is 85. Cosine is adjacent divided by hypotenuse. The "adjacent" side is the unlabelled length. We find this by using the Pythagorean Theorem:

b = \sqrt{85^2-(-13)^2} =\sqrt{7225-169} =\sqrt{7056} =84

So, cos(Θ) = 84/85

Hope this helps!

6 0
3 years ago
will give brainliest!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1
Phoenix [80]

Answer:

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Step-by-step explanation:

7 0
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Answer:

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Step-by-step explanation:

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4 0
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