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4 years ago

Gabby bought 5.15 kg of apples and 1.6 kg of oranges how much fruit did she buy in all

Mathematics

2 answers:

solmaris [256]4 years ago

8 0

Answer:

6.75kg of fruit

Step-by-step explanation:

5 + 1 = 6

.15 + .6 = .75

6 + .75 = 6.75

kipiarov [429]4 years ago

3 0

Answer:

6.75

Step-by-step explanation:

Add 5.15 and 1.60

5.15

1.60

6.75

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Two people took turns tossing a fair die until one of them tossed a 6. PersonA tossed first, B second, A third, and so on. Given

Gennadij [26K]

Answer: 0.0965

Step-by-step explanation:

This would happen if:

First toss: Here we must have any number that is not 6.

the options are 1, 2, 3, 4, 5 so the probablity is p1 = 5/6

The same happens for the second toss, p2 = 5/6

and for the third one: p3 = 5/6

for the fourth toss, person B must roll a 6, so the probability here is p4 = 1/6

Now, the joint probability is equal to the product of the probabilities for each toss, this is:

P = p1*p2*p3*p4 = (5/6)^3*(1/6) = 0.0965

4 0

3 years ago

The range is equal to two thirds the domain ,reduced by three

Annette [7]

Answer:

$y=\frac{2}{3}x-3$

Step-by-step explanation:

Let's assign variables to the various variables in the equation.

Let's say domain will be the variable $x$ .

Let's say range will be the variable $y$ .

Range is equal to two-thirds of the domain, so domain times two-thirds will equal the range.

$y=\frac{2}{3}x$

This should also be reduced by three, which is just another way of saying subtract.

$y=\frac{2}{3}x-3$

5 0

3 years ago

Find a solution to the following initial-value problem: dy dx = y(y − 2)e x , y (0) = 1.

Veseljchak [2.6K]

This equation is separable, as

$\dfrac{\mathrm dy}{\mathrm dx}=y(y-2)e^x\implies\dfrac{\mathrm dy}{y(y-2)}=e^x\,\mathrm dx$

Integrate both sides; on the left, expand the fraction as

$\dfrac1{y(y-2)}=\dfrac12\left(\dfrac1{y-2}-\dfrac1y\right)$

Then

$\displaystyle\int\frac{\mathrm dy}{y(y-2)}=\int e^x\,\mathrm dx\implies\frac12(\ln|y-2|-\ln|y|)=e^x+C$

$\implies\dfrac12\ln\left|\dfrac{y-2}y\right|=e^x+C$

Since $y(0)=1$ , we get

$\dfrac12\ln\left|\dfrac{1-2}1\right|=e^0+C\implies C=-1$

so that the particular solution is

$\dfrac12\ln\left|\dfrac{y-2}y\right|=e^x-1\implies\boxed{y=\dfrac2{1-e^{2e^x-2}}}$

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3 years ago

Hector surveyed 500 people and asked them how far they drive to work and what is the last digit of their phone number. He used t

IRISSAK [1]

Answer:postive

Step-by-step explanation:

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3 years ago

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zepelin [54]

Answer:

2/3

Step-by-step explanation:

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3 years ago

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