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rodikova [14]
3 years ago
10

Is 0.54 a rational number? Why or why not?

Mathematics
2 answers:
skelet666 [1.2K]3 years ago
5 0
It is a rational number because it ends which is a characteristic of a rational number. If you were to convert it to a fraction, the simplest form would be 27/50.
 
Anna71 [15]3 years ago
5 0
0.54 is a rational number because in can be written as 54/100 and both 54 and 100 are integers
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34

Step-by-step explanation:

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#6. How do you do it?
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Identify the x-intercepts of the function below f(x)=x^2+12x+24
damaskus [11]

<u>ANSWER:  </u>

x-intercepts of  \mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})

<u>SOLUTION:</u>

Given, f(x)=x^{2}+12 x+24 -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

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X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here, for (1) a = 1, b= 12 and c = 24

X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}

\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}

Hence the x-intercepts of  \mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})

8 0
3 years ago
7x+3+6x+11 i need help solving this problem
____ [38]
Step-by-step solution:

7x + 3 + 6x + 11 = 0

7x + 6x + 11 + 3 = 0

13x + 11 + 3 = 0

13x + 14 = 0

13x = 0 - 14

13x = -14

x = -14 / 13

x = -1.077 approx.




Hope it helped,



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3 years ago
Maria Spent 40 minutes chatting online. How many minutes did she spend playing games?
Aleks [24]
She spent 10 minutes. 25% x 40 = 10.
5 0
3 years ago
Read 2 more answers
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