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pav-90 [236]
2 years ago
8

Standard form of the equation that goes through (3, -1) with a slope of -1, please!

Mathematics
1 answer:
11111nata11111 [884]2 years ago
7 0

Answer:

x+y=2

Step-by-step explanation:

Standard Form: ax+by=c

For most convenience start with slope-intercept form: y=mx+b

1. -1 = -1(3)+b -  solve for b

b=2

y= -1x+2 (slope-intercept form)

2. Now convert to standard form

Add 1x to both sides:

1x+y=2

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What is the minimum cuts  needed to cut a circle into 8  equal parts ?

A : 4 cuts

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3 years ago
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John has decided to prepare an old field for his son's new horse. the length of the field is 10 meters less than 4 times its wid
tatuchka [14]

Answer: The total money invested in the field will be $1,623.80

Step-by-step explanation:

step 1

Find the dimensions of the field

Let

x -----> the length of the field

y -----> the width of the field

p=2(x+y)

p(4.80)=1,584

p=330m

we know that

The perimeter of the field is equal to

so

330=2(x+y)----> equation A

x=4y-10 ------> equation B

substitute equation B in equation A and solve for y

330=2(4y-10+y)

165=(5y-10)

5y=165+10

y+35

Find the value of x

x=4(35)-10+130

therefore

The length of the field is 130 meters and the width of the field is 35 meters

step 2

Find the area of the field

The area of the field is

A=xy

substitute

A=(130)(35)=4,550m2

step 3

Find the number of bags of seed

Divide the area by 460

4,550/460=9.89 bags

Round up to the nearest whole number

9.89 bags=10 bags

step 4

Find the cost of the seed

(10 )(3.98)=$19.8

step 5

Find the total money invested in the field

1,584+$39.8=$1,623.80

7 0
1 year ago
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How do i calculate the first quartile and the third quartile??? <br> !!!please help!!!
diamong [38]

Answer: The Median: 78, The First Quartile: 63, and The Third Quartile: 99

Step-by-step explanation: Ok, so let's put the data set from least to greatest....

(63, 63, 76,) (77, 79,) (84, 99, 99)

First Quartile              Third Quartile

First, let's find the median, since you made a little mistake...

77 + 79 = 156

156 ÷ 2 = 78

The median is 78!

Now, let's determine the first quartile and the third quartile.

For the the first quartile/third quartile it'll be the middle number, if it's even we'll do the same extra step just like we'll do for the median. In this case it's not even therefore...

First Quartile: 63

Third Quartile: 99

I hope this helps!

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2 years ago
Compare -10 and 0 using less than, greater than sign, or =
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Answer:

-10<0

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