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Anna007 [38]
3 years ago
6

How is a rational number that is not an integer different from a rational number that is an integer?

Mathematics
1 answer:
vladimir1956 [14]3 years ago
6 0
By looking at my notes, comparing and contrasting rational numbers that are integers to rational numbers that aren't is quite simple. Rational numbers are practically almost every single number in the number system. So...rational numbers that aren't integers would be fractions, decimals, and percentages. But rational numbers that are integers are whole numbers, either negative or positive. Hope this helps!
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F(x)=2x+3/4x+5 find f(-9)<br><br>pls solve it ​
Marysya12 [62]

Answer:

15/31

Step-by-step explanation:

substitute -9 were there's x in the function

f(-9)=2(-9)+3/4(-9)+5

=-18+3/-36+5

=-15/-31

the negatives cancel giving you

15/31

4 0
3 years ago
Help please on this question!!
Alika [10]

Answer:

82

Step-by-step explanation:

50+32 =82 and this has to be longer so this is me making it longer

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9–5(x+4)=3(2–x) help!!!!!1
netineya [11]

Answer:

-17/2 =x

Step-by-step explanation:

9–5(x+4)=3(2–x)

Distribute

9 - 5x - 20 = 6 -3x

Combine like terms

-5x-11 = 6-3x

Add 5x to each side

-5x-11 +5x = 6-3x+5x

-11 = 6+2x

Subtract 6 from each side

-11-6 = 6+2x-6

-17 = 2x

Divide by 2

-17/2 = 2x/2

-17/2 =x

3 0
3 years ago
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Teresa is playing a video game. She earns 10 points when she completes Level 1. Each time she completes a level, she earns three
lesya [120]

Answer: 7290

Step-by-step explanation:

Three times is asking you to multiply the points before them by three. Level one, as we know is 10. Then, to get level two's points, you would multiply 10 by 3, to get 30, & so on.

Level One:10

Level Two: 10x3=30

Level Three: 30x3=90

Level Four: 90x3=270

Level Five: 270x3=810

Level Six: 810x3=2430

Level Seven: 2430x3= 7290

*** If you are still confused, comment on this question, & I will be happy to walk you through the whole question. ***

6 0
3 years ago
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Help guys with the question
Naya [18.7K]

Answer:

\sin\Big(\dfrac{\theta }{2}\Big) = \dfrac{2\sqrt 5}{5}

Step-by-step explanation:

\cos(2x) = \cos^2 x-\sin^2 x = 1-2\sin^2 x \\ \\ \cos(x) = 1-2\sin^2 (\frac{x}{2}) \\ \\ \Rightarrow \sin^2 (\frac{x}{2}) = \dfrac{1-\cos(x)}{2}\\ \\ \sin(\frac{x}{2}) = \pm \sqrt{\dfrac{1-\cos(x)}{2}},\quad x\in [\frac{3\pi }{2},\pi] \Rightarrow \frac{x}{2}\in [\frac{3\pi}{4},\frac{\pi}{2}]\\ \\ \Rightarrow \sin(\frac{x}{2}) > 0 \Rightarrow \sin(\frac{x}{2}) = \sqrt{\dfrac{1-(-\frac{3}{5})}{2}} \Rightarrow \sin(\frac{x}{2}) = \sqrt{\dfrac{8}{10}}=\dfrac{2\sqrt 2}{\sqrt{10}} = \\ \\ =\dfrac{2\sqrt 5}{5}

7 0
3 years ago
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