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Anna007 [38]
3 years ago
6

How is a rational number that is not an integer different from a rational number that is an integer?

Mathematics
1 answer:
vladimir1956 [14]3 years ago
6 0
By looking at my notes, comparing and contrasting rational numbers that are integers to rational numbers that aren't is quite simple. Rational numbers are practically almost every single number in the number system. So...rational numbers that aren't integers would be fractions, decimals, and percentages. But rational numbers that are integers are whole numbers, either negative or positive. Hope this helps!
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The interior angles formed by the sides of a quadrilateral have measures that sum to 360°.
Sergio039 [100]
Add 3x and 2x together to get 5x. Then do 88+108-6 and you get 190. To find x now all you have to do is use 5x+190=360 to get x.
360 -190= 170 now you have 5x=170 divide 170/5 and that will give u the value of x.
7 0
3 years ago
Read 2 more answers
F(x)=-x^2+8x+15 ...?
rusak2 [61]
Here i how I would do it:<span>f(x)=−<span>x2</span>+8x+15</span>
set f(x) = 0 to find the points at which the graph crosses the x-axis. So<span>−<span>x2</span>+8x+15=0</span>
multiply through by -1<span><span>x2</span>−8x−15=0</span> <span>(x−4<span>)2</span>−31=0</span> <span>x=4±<span>31<span>−−</span>√</span></span>
So these are the points at which the graph crosses the x-axis. To find the point where it crosses the y-axis, set x=0 in your original equation to get 15. Now because of the negative on the x^2, your graph will be an upside down parabola, going through<span>(0,15),(4−<span>31<span>−−</span>√</span>,0)and(4+<span>31<span>−−</span>√</span>,0)</span>
To find the coordinates of the maximum (it is maximum) of the graph, you take a look at the completed square method above. Since we multiplied through by -1, we need to multiply through by it again to get:<span>f(x)=31−(x−4<span>)2</span></span><span>
Now this is maximal when x=4, because x=4 causes -(x-4)^2 to vanish. So the coordinates of the maximum are (4,y). To find the y, simply substitute x=4 into the equation f(x) to give y = 31. So it agrees with the mighty Satellite: (4,31) is the vertex.</span>
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3 years ago
Can I get help......​
Ivenika [448]
The answer is C -208 degrees Fahrenheit!
6 0
3 years ago
Write a polynomial as the sum of the monomials and write it in standard form. For each of the above specify the degree of the re
klio [65]

Answer:

2b³ +2a -2c . . . . degree 3 polynomial

Step-by-step explanation:

The monomials are ...

... 4a . . . . degree 1 in a

... -5b·b² = -5b³ . . . . degree 3 in b

... -3c . . . . degree 1 in c

... 7b³ . . . . degee 3 in b (like term with -5b³)

... +c . . . . degree 1 in c (like term with -3c)

... -2a . . . . degree 1 in a (like term with 4a)

So, we have 3 pairs of like terms. The like terms can be combined by summing their coefficients.

The degree of the polynomial is that of the highest-degree term. (Here, the b³ term makes it a polynomial of degree 3.)

... 4a -2a = (4-2)a = 2a . . . . combining the "a" terms

... -5b³ +7b³ = (-5+7)b³ = 2b³ . . . . combining the b³ terms

... -3c +c = (-3 +1)c = -2c . . . . combining the "c" terms

In standard form, we write the highest-degree term first. Follwing terms are in order by decreasing degree. It is convenient, but perhaps not required, to then write the terms of the same degree in alphabetical order.

... = 2b³ +2a -2c . . . . a 3rd degree polynomial

7 0
3 years ago
If (8,-2) is on the graph of F(x), which point must be on the graph of the inverse funtion F^-1(x)?
FromTheMoon [43]
If the point ( 8,-2) is on F(X) that a point ( -2,8) must be on the graph of the inverse fraction F^-1 (x) because the invers of a function is found by inversing the coordinate x and y. 


5 0
4 years ago
Read 2 more answers
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