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nydimaria [60]
3 years ago
9

Find the balance in the account after the given period. ​$2000 principal earning 6​% compounded​ annually, for 8 years. The bala

nce after 8 years will be ​$__?
Mathematics
2 answers:
Harman [31]3 years ago
8 0
Do 2000 divided by 8 than divided that by 6%
Alja [10]3 years ago
4 0
For this case we use the following formula:
 P (t) = P (1 + r / n) ^ (n * t)
 Substituting values we have:
 P (8) = 2000 * (1 + 0.06 / 1) ^ (1 * 8)
 P (8) = 3187.696149
 Rounding off we have:
 P (8) = 3187.7 $
 Answer:
 
The balance after 8 years will be $ 3187.7
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QveST [7]

Answer:

\frac{5}{-8} or -0.625

Step-by-step explanation:

The slope formula is as shown:

m=\frac{y_{2} -y_{1} }{x_{2} -x_{1}}

We can have A = (x_{1},y_{1}) and B = (x_{2},y_{2}).

We can hence plug in the values into the formula to get m=\frac{3-(-2)}{-5-3}.

As we simplify, the negatives on the top row cancel out to give us an addition sign instead and we add them.

m=\frac{5}{-8}

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A walkway is being constructed using square cement tiles that each have an area of 19.0 ft2. 6 tiles will be lined up end to end
allochka39001 [22]

Answer:

26.3 feet

Step-by-step explanation:

We have to first find the length of the side of each tile.

The area of each tile is 19.2 ft^2.

The area of a square is:

A = L^2

where L = length of side

Therefore:

19.2 = L^2\\\\L = \sqrt{19.2} =  4.38 feet

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7 0
3 years ago
Determine the equation of the circle graphed below.
sergij07 [2.7K]

Answer:

Equation = (x - 6 )² + ( y + 3 )² = 9

Step-by-step explanation:

The circle passes through ( 6, 0) and  ( 6 , -6)

They are the coordinates of the diameter.

Using this we can find the centre of the circle.

<u>Find the centre of the circle.</u>

Centre of the circle is the mid- point of (6, 0) and ( 6, -6)

      Centre = (\frac{x_1+x_2}{2} , \frac{y_1 + y_2}{2})

                 =(\frac{6 + 6}{2}, \frac{0 + (-6)}{2})\\\\=(6, -3)

<u>Find the radius of the circle.</u>

Radius = \frac{Diameter }{2}

Diameter is the distance between the points (6 , 0) and ( 6, - 6)

Diameter = \sqrt{(x_2 - x_1)^2+ (y_2 - y_1)^2\\}

               =\sqrt{(6-6)^2 + (-6 -0)^2}\\\\=\sqrt{0 + 36} \\\\= 6

Therefore,

    Radius ,r = \frac{6}{2} = 3

<u>Standard equation of a circle:</u>

<u></u>(x - a)^2 + (y - b)^2 = r^2 \ where \ (a , b) \ is \ the\ centre \ coordinates.<u></u>

Therefore , equation of the circle ;

                    (x - 6)^2 + (y + 3)^2 = 3^2\\\\(x -6)^2 + (y + 3)^2 = 9

6 0
3 years ago
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