<span>2≤x≤8</span>
<span>−4≤<span>f′</span>(x)≤5</span>
f is continuous in differentable on [2,8] so we know there is c btw 2 and 8 such that
<span><span>f′</span>(c)=<span><span>f(8)−f(2)</span><span>/8−2</span></span></span>
And we know
<span>−4≤<span>f′</span>(c)≤5</span>
=> we have
<span>−4≤ <span><span>f(8)−f(2)</span><span>/8−2</span></span> ≤<span>5</span></span>
Answer: 
Step-by-step explanation:
The proccedure shown in the problem is applied to solve for x and calculate its value.
One of the equations shown in the problem is:

To solve for x you must_
- Add 6 to both sides of the equations:


- Then you must divide by -3:

Then the answer is: 
Answer:140%, 2.4
Step-by-step explanation:
Opening stock in 2010=$25
Closing stock in2010=$60
Percentage increase is $60-$25/25$
Percentage increase= $35/$25
Percentage increase= 1.4*100%
Percentage increase= 140%
Annual multiplier =$60/$25
Annual multiplier =2.4
Answer:
s(2) =5x+127
Step-by-step explanation:
127 is your y-intercept
5 is your coefficient
x is variable in weeks
s=$137