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Ne4ueva [31]
2 years ago
8

At a grocery store 4.5 pounds of meat cost $14.67. What is the cost of the meat per pound?

Mathematics
1 answer:
Elan Coil [88]2 years ago
8 0

Answer:

$3.26

Step-by-step explanation:

If 4.5 pounds cost $14.67

You divide 14.67 by 4.5 which gives you 3.26

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(3x +2)<br> 2x<br> (x, sol<br> (2x+1001
eduard

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3 years ago
Mrs. Jacobs purchased a 5 pound package of ground beef for $12.40. She decided to use 8 ounces each day for dinner recipes. What
WITCHER [35]
There is 16 ounces in 1 pound. so you would want to divide 12.40 by 5 = $2.48 . so its $2.48 for a pound divide by 2 and you answer would be $1.24... i hope that helps
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The diameter of a circle is 8 centimeters what is the circles area
Rina8888 [55]

Answer:

50.27

Step-by-step explanation:

You split 8 in half to find radius, and multiply that by pi.

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3 years ago
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I suck at math and i really need help asap!
AlladinOne [14]

Answer:

2

Step-by-step explanation:

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3 years ago
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Does going to a private university increase the chance that a student will graduate with student loan debt? A national poll by t
Snowcat [4.5K]

Answer:

Null hypothesis:p \leq 0.69  

Alternative hypothesis:p > 0.69  

Step-by-step explanation:

1) Data given and notation

n=1500 represent the random sample taken

X represent the number of graduates that had student loan debt in 2014

\hat p=0.71 estimated proportion of adults that said that it is morally wrong to not report all income on tax returns

p_o=0.69 is the value that we want to test

\alpha represent the significance level  

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that if there was a significant increase in the proportion of student loan debt for public and nonprofit colleges in 2014 respect to the value of 2013.:  

Null hypothesis:p \leq 0.69  

Alternative hypothesis:p > 0.69  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.71 -0.69}{\sqrt{\frac{0.69(1-0.69)}{1500}}}=1.675  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed is \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>1.675)=0.047  

If we compare the p value obtained and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults that said that it is morally wrong to not report all income on tax returns  is not significantly higher than 0.69.  

5 0
3 years ago
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