4+8+3 would be 15 because 4 plus 8 is 12 and 12 plus 3 is 15
Hope this helps
Answer:
27.2x - 61.6
Step-by-step explanation:
16x + 5.6(2x - 11)
16x + 11.2x - 61.6
27.2x - 61.6
Answer:
Step-by-step explanation:
We would apply the formula for binomial distribution. It is expressed as
P(x = r) = nCr × q^(n - r) × p^r
Where
n = number of samples
p = probability of success.
q = probability of failure
From the information given,
n = 12
p = 90% = 90/100 = 0.9
q = 1 - p = 1 - 0.9 = 0.1
28) Probability that at least 10 are ripe within 4 days is expressed as
P(x ≥ 10) = P(x = 10) + P(x = 11) + P(x = 12)
P(x = 10) = 12C10 × 0.1^(12 - 10) × 0.9^10 = 0.23
P(x = 11) = 12C11 × 0.1^(12 - 11) × 0.9^11 = 0.38
P(x = 12) = 12C12 × 0.1^(12 - 12) × 0.9^12 = 0.28
P(x ≥ 10) = 0.23 + 0.38 + 0.28 = 0.89
29) Probability that no more than 9 are ripe within 4 days is expressed as
P(x ≤ 9) = 1 - P(x ≥ 10)
P(x ≤ 9) = 1 - 0.89 = 0.11
Answer:
○ Subtract 8 from both sides, then divide both sides by 1/3
Step-by-step explanation:
Perhaps the usual sequence of steps is ...
add 8:
3y = 27
divide by 3 (equivalently, multiply by 1/3)
y = 9
___
If the division by 3 is done first, then the constant on the left becomes -8/3, so cancelling it requires adding 8/3 to both sides of the equation.
_____
If you do the last suggestion, you get ...
subtract 8 from both sides:
-16 +3y = 11
divide both sides by 1/3:
-48 +9y = 33 . . . . . . . does not solve the equation completely
What is the average weight of the adult elephants in the exhibit? This is the correct statistical question.
<h3>What is the statistical questions?</h3>
Statistical question is that type of question which have more than one possible answers.
The answer of statistical question is the collection of various points of data.
The answer of statistical question depends on variety and situations.
The answer of statistical question may be range . Answer of statistical question are more than one.
What is the average weight of the adult elephants in the exhibit?
This is the correct statistical question.
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