Give the values of a, b, and c needed to write the equation's general form. 2/3(x - 4)(x + 5) = 1

2 answers:

5 0

Rearranging what you have you get

$\frac{2}{3}x^2+\frac{2}{3}x-\frac{43}{3}=0$ , thus

$a=\frac{2}{3}, b=\frac{2}{3}, c=\frac{43}{3}$

ale4655 [162]3 years ago

4 0

The first step is to write this equation into general form. The general form of an equation is:

ax^2 + bx + c = 0

To make this equation to general form, you have to simplify the equation first.

2/3(x-4) (x+5) = 1

2/3 (x^2 + 5x – 4x – 20) = 1

2/3(x^2 + x -20) = 1

2/3x^2 + 2/3x – 40/3 = 1

2/3x^2 + 2/3x – 40/3 – 1 = 0

2/3x^2 +2/3x – 43/3 = 0

Therefore, a = 2/3 ; b = 2/3 ; c = -43/3

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John plays basketball at the local gym. The gym charges a monthly membership fee of $15.00, plus each player pays $2.50 per game

Katyanochek1 [597]

Answer:
Step-by-step explanation:
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3 0

3 years ago

Read 2 more answers

Solve for y in terms of x.

krek1111 [17]

Answer:

$y=\frac{3}{2} x+6$

Step-by-step explanation:

We are given the following equation and we are supposed to solve y in terms of x. It simpler terms, it means that we have to make y the subject of the equation while x being used in it as it is:

$\frac{2}{3} y-4=x$