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wlad13 [49]
3 years ago
6

Find the distance between the two points K(-7,5), H(5,7)

Mathematics
1 answer:
shutvik [7]3 years ago
8 0

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ K(\stackrel{x_1}{-7}~,~\stackrel{y_1}{5})\qquad H(\stackrel{x_2}{5}~,~\stackrel{y_2}{7})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ KH=\sqrt{[5-(-7)]^2+[7-5]^2}\implies KH=\sqrt{(5+7)^2+(7-2)^2} \\\\\\ KH=\sqrt{144+4}\implies KH=\sqrt{148}\implies KH\approx 12.17

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if a rectangle has an area of 30 square meters and a perimeter of 34 meters . what is the dimensions of the rectangle?
timama [110]
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2(L+W)=34

L+W=17 so we can say

L=17-W

A=LW using L from above

A=(17-W)W

A=17W-W^2 and A=30 so

30=17W-W^2

W^2-17W+30=0

W^2-2W-15W+30=0

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3 years ago
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GenaCL600 [577]

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5 0
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Eva8 [605]
The first step to solving this is converting these mixed numbers into improper fractions. You would do that by multiplying the denominator by the whole number and adding the numerator to that number; this number replaces the numerator. It would look something like this:

1 8/10   -->   18/10
2 2/5   -->   12/5

Now, to subtract the second fraction from the first one, the denominators of both fractions must be the same. We can make them the same by multiplying the second fraction by 2:

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The answer is negative 3/5.

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5 0
2 years ago
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