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Levart [38]
3 years ago
12

Plz help me get the right answer to these

Mathematics
2 answers:
taurus [48]3 years ago
6 0

Answer:

<h2>x = -20</h2>

Step-by-step explanation:

3+\dfrac{1}{5}x=-1\qquad\text{subtract 3 from both sides}\\\\\dfrac{1}{5}x=-4\qquad\text{mulatiply both sides by 5}\\\\5\!\!\!\!\diagup^1\cdot\dfrac{1}{5\!\!\!\!\diagup_1}x=(5)(-4)\\\\x=-20

const2013 [10]3 years ago
5 0

Equation: 3+1/5 x=-1

Step 1. You need to simplify both sides of the equation.

1 /5  x+3=−1

Step 2: Subtract 3 from both sides of the equation.

1 /5  x+3−3=−1−3

1 /5  x=−4

Step 3: Multiply both sides of the problem by 5.

5 x ( 1 /5  x)=(5) x (−4)

x=−20

Answer: x=-20

Hope I could help!

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Solve the following equation. Then place the correct number in the box provided. 2(P + 1) &gt; 7 + P
Deffense [45]
2(P + 1) > 7 + P
2P + 2 > 7 + P
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8 0
3 years ago
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Given TS¯¯¯¯¯¯¯ and TU¯¯¯¯¯¯¯ are midsegments, PR=18.2, TS=6.5. Find QU . A. 9.1 B. 3.25 C. 13 D. 6.5
AleksAgata [21]

Answer:

The correct option is;

D. 6,5

Step-by-step explanation:

TS and TU are midsegments

Segment PR = 18.2

Segment TS = 6.5

Given that TS is the midsegment of PR and PQ, therefore, TS = 1/2×QR

Which gives;

Segment QR = 2×TS = 2 × 6.5 = 13

Segment QR = 13

Given that TU is a midsegment to PQ and QR, we have that QU = UR

Segment QR = QU + UR (segment addition postulate)

Therefore, QR = QU + QU (substitute property of equality)

Which gives;

QR = 2×QU

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Segment QU = 13/2 = 6.5

The length of segment QU is 6.5.

5 0
3 years ago
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Delvig [45]

Answer:

117

Step-by-step explanation:

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Step-by-step explanation:

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Describe the zero product property and explain how tu use it to solve (2x + 10) (x - 7) = 0
Korolek [52]

Answer:

See below

Step-by-step explanation:

Basically, when you have a product to two factors set equal to 0, you can use the Zero Product Property and make two separate equations, both set equal to 0, to find the roots for each factor:

2x+10=0\\2x=-10\\x=-5

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Notice that by plugging these roots back into the equation, either factor will be 0, making the whole expression 0:

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8 0
2 years ago
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