The rates are equivalent because both of them do 30 jumping jacks a minute.
A + s = 444
s = 2a
a + 2a = 444
3a = 444
a = 444/3
a = 148 <== adults
s = 2a
s = 2(148)
s = 296 ...students
Answer:
48 days
Step-by-step explanation:
Given that :
Sumiko runs bleachers every 6 days
Jandella runs bleachera every 16 days
The soonest they will see each other again is in days can be obtained by getting the lowest common multiple of 6 and 16
Multiples of
6 : 6, 12, 18, 24, 30, 36, 42, 48, 54,...
16 : 16, 32, 48, 64,...
Lowest common multiple of 6 and 16 = 48
Hence, the soonest they'll see each other again is in 48 days