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eimsori [14]
3 years ago
12

Write the equation of the line perpendicular to y=4/3x+1 that passes through the points (-8, 4).

Mathematics
1 answer:
Murrr4er [49]3 years ago
3 0

Answer:

The equation is;

y = -3/4x + 12

Step-by-step explanation:

The general form for the equation of a straight line is;

y = mx + b

where m is the slope and b is the y-intercept

With respect to this question;

4/3 is the slope and 1 is the intercept

If two lines are perpendicular, then the product of their slopes is -1

Mathematically;

4/3 * m2 = -1

m2 = -3/4

So to find the equation of this second line, we use the point slope form

This is;

y-y1 = m(x-x1)

y-4 = -3/4(x + 8)

y- 4 = -3/4x + 8

y = -3/4x + 12

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Answer:

3.65 \leqslant x \leqslant 3.75

Step-by-step explanation:

The error in rounding a number is half of the unit of measure.

The number was rounded to the nearest 0.1 unit so the error is 1/2×0.1, which equals 0.05.

Now we add 3.7 and 0.05, which equals 3.75 and we also take 3.7 - 0.05, which equals 3.65

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3.65 \leqslant x \leqslant 3.75

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Scorpion4ik [409]

Answer:

Area of the circle=200.96 km^2

Step-by-step explanation:

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