<h2>(1)</h2><h2> =(a+b)(3c-d)</h2><h2> =a(3c-d)+b(3c-d)</h2><h2> =3ac-ad+3bc-bd</h2>
<h2>(2)</h2><h2> =(a-b)(c+2d)</h2><h2> =a(c+2d)-b(c+2d)</h2><h2> =ac+2ad-bc-2bd</h2>
<h2>(3)</h2><h2> =(a-b)(c-2d)</h2><h2> =a(c-2d)-b(c-2d)</h2><h2> =ac-2ad-bc+2bd</h2>
<h2>(4)</h2><h2> =(2a+b)(c-3d)</h2><h2> =2a(c-3d)+b(c-3d)</h2><h2> =2ac-6ad+bc-3bd</h2>
Answer:
I don't think it is
Step-by-step explanation:
tell me if I'm wrong
Answer:
The mean weight of the cats is 11.42 (rounded)
Step-by-step explanation:
To find the mean, you add up all the weights (12, 12, 9, 9, 11, 11, 16) and then divided the sum (80) of the weights by the number of cats (7)
12+12+9+9+11+11+16= 80
80 ÷ 7= 11.42857143 (I rounded my answer to 11.42)
I hope this was helpful. Have a wonderfull rest of your day!
X = k x y
21 = k x 3
k = 7
x = 7y
x = 7(10)
x = 70
Answer:
Step-by-step explanation:
The chines man ate the dog
