You can get a vertical asymptote at x=1 using y = 1/(x-1)
You can generate a hole at x=3 by multiplying by (x - 3/(x - 3) which is undefined at x=3 but otherwise equals 1
You can move the horizontal asymptote up to y=2 by adding 2

y = (x - 3)/((x - 1)(x - 3)) + 2

5 0

3 years ago

A pack of 13 candles is priced at $78. At that rate, how much would only 10 candles cost?

Sphinxa [80]

Answer:

78/13 = 6 (is the price of one candle)

6(price) x 10(candles) =60 is the answer

Hope it helped

8 0

3 years ago

Slope = 2/5; passes through (-3,1)

nydimaria [60]

Presumably we're after the line with that slope through that point. In general the line through $(a,b)$ with slope $m$ is

$y-b = m(x-a)$

Here we have $a=-3, b=1, m=\frac 2 5$

$y - 1 = \frac 2 5 (x--3)$

$y = \frac 2 5 x + \frac 6 5 + 1$

$y = \frac 2 5 x + \frac{11}{5}$

Check: The slope is clearly $\frac 2 5$
so we check

$y = \frac 2 5 (-3) +\frac{11}{5} = \frac 5 5 = 1 \quad\checkmark$

8 0

3 years ago

Cate and elena were playing cards

Delicious77 [7]

There were...
11cards left.
heres why.
they started with 24 cards....
so...
24+8=32
32-12=20
20-9=11

Hope i helped!!! :)
Mark me as brainliest if i helped XD

6 0

3 years ago

Help would be much appreciated ​

Help would be much appreciated