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Anit [1.1K]
2 years ago
12

A cookie factory uses 7/10 of a barrel of oatmeal in each batch of cookies. The factory used 4 9/10 barrels of oatmeal yesterday

. How many batches of cookies did the factory make?
Write your answer as a fraction or as a whole or mixed number.
Mathematics
1 answer:
melamori03 [73]2 years ago
5 0

Answer: 7 BATCHES

Step-by-step explanation: to produce one batch it takes 7/10 of oatmeal

Now the factory uses 4 9/10 batch of oatmeal

1=7/10 OATMEAL

X=4 9/10 OATMEAL

X=(7/10*1)/4 9/10

=4 9/10*10/7

=490/70

=7

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yarga [219]

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your fraction would be 27/9 which simplifies to 3.

Juan's dog is 3 times bigger than Peters!

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4 years ago
Help me this question is very confusing no wrong answers please
olga_2 [115]

Answer:

10

Step-by-step explanation:

maximum= most walked

then minimum would be least amount walked

4 0
3 years ago
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Are the two triangles similar? How do you know?
Bess [88]
There are several conditions where triangles can be proved similar:

AA - where two of the angles are same.

SAS - where two sides of a triangle compare to the corresponding sides in the other are in same proportion, and the angle in the middle are equal.

SSS - Where all sides in a triangle and the corresponding sides are in the same proportion.

In the case above, we can only use the method of SAS, as only two sides of the triangles are given.

<HMG = <JMK (vertically opposite angles)

HM/MK = 8/12 = 2/3

GM/MJ = 6/9 = 2/3

As the two sides of a triangle comparing to the corresponding sides in the other are in same proportion, and the angle in the middle are equal, the above triangles are similar, with the prove of SAS.

Therefore, the answer is C.yes by SAS.

Hope it helps!
7 0
3 years ago
Find the sum. 2/5 + 1/2​
dybincka [34]
2/5 + 1/2

4+5 / 10 • look for the LCD of 5 and 2
which is 10 then 5 goes 2
times into 10 the multiply by 2
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Therefore the sum of 2/5 + 1/2 =9/10
5 0
3 years ago
Read 2 more answers
It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
Molodets [167]

Answer:

10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 375 minutes and standard deviation 68 minutes. So \mu = 375, \sigma = 68

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes?

So n = 6, s = \frac{68}{\sqrt{6}} = 27.76

This probability is 1 subtracted by the pvalue of Z when X = 410.

Z = \frac{X - \mu}{s}

Z = \frac{410 - 375}{27.76}

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So there is a 1-0.8962 = 0.1038 = 10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

Lean

Normally distributed with mean 522 minutes and standard deviation 106 minutes. So \mu = 522, \sigma = 106

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes?

So n = 6, s = \frac{106}{\sqrt{6}} = 43.27

This probability is 1 subtracted by the pvalue of Z when X = 410.

Z = \frac{X - \mu}{s}

Z = \frac{410 - 523}{43.27}

Z = -2.61

Z = -2.61 has a pvalue of 0.0045.

So there is a 1-0.0045 = 0.9955 = 99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

6 0
4 years ago
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