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kaheart [24]
3 years ago
11

Please help. I'm dumb and can't understand this.

Mathematics
2 answers:
Fed [463]3 years ago
8 0

Answer: 5 years

              14,800 students enrolled

Step-by-step explanation:

Let x represent the number of years and

Let y represent the number of students enrolled

College A: y = 12,300 + 500x

College B: y = 18,550 - 750x

Use substitution Method to solve:

12,300 + 500x = 18,550 - 750x

            +750x                +750x

12,300 + 1250x = 18,550

-12,300               -12,300

              1250x = 6250

                      x = 5

Input x = 5 into one of the equations to solve for y.

y = 12,300 + 500x

  = 12,300 + 500(5)

  = 12,300 + 2500

  = 14,800

Read more on Brainly.com - brainly.com/question/12387804#readmore

xxTIMURxx [149]3 years ago
5 0

Answer: A. 2073

B. 79700

Step-by-step explanation:

Let x represent the number of years that it will take the two colleges to have the same enrollment.

In 2005 there were 11,700 students at college A, with a projected enrollment increase of 1000 students per year. This means that the total number of students that would be enrolled at college A in x years time would be

1000x + 11700

In the same year, there were 32,100 students at college B, with a projected enrollment decline of 700 students per year. This means that the total number of students that would be enrolled at college B in x years time would be

700x + 32100

For the two colleges to have the same enrollment, then

1000x + 11700 = 700x + 32100

1000x - 700x = 32100 - 11700

300x = 20400

x = 20400/300

x = 68

The year would be 2005 + 68 = 2073

B) The number of students that will be enrolled in the colleges is

1000 × 68 + 11700

= 79700

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kenny6666 [7]
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Suppose it is known from large amounts of historical data that X, the number of cars that arrive at a specific intersection duri
Andrew [12]

Answer:

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b)  P(x = 2) =0.04661

Step-by-step explanation:

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3 0
3 years ago
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