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2 years ago

kala used 12.86 gallons of fuel while driving now 1.6 gallons are left how much fuel did kala car have before her trip

Mathematics

1 answer:

Troyanec [42]2 years ago

8 0

Her car had 14.46 gallons of fuel before her trip because 12.86+1.6=14.46

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Item 4

Simora [160]

Answer:

270 s

Step-by-step explanation:

4 minutes = 240s

add the other 30s

boom

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2 years ago

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Simplify: 3^2 · 3^4 A) 3^6 B) 3^8 C) 3^2 D) 9^6

Greeley [361]

Answer:

3^6

Step-by-step explanation:

3^2 * 3^4

You add the exponents together.

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2 years ago

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Please help?

Mazyrski [523]

Answer:

$23\sqrt{3}\ un^2$

Step-by-step explanation:

Connect points I and K, K and M, M and I.

1. Find the area of triangles IJK, KLM and MNI:

$A_{\triangle IJK}=\dfrac{1}{2}\cdot IJ\cdot JK\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 2\cdot 3\cdot \dfrac{\sqrt{3}}{2}=\dfrac{3\sqrt{3}}{2}\ un^2\\ \\ \\A_{\triangle KLM}=\dfrac{1}{2}\cdot KL\cdot LM\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 8\cdot 2\cdot \dfrac{\sqrt{3}}{2}=4\sqrt{3}\ un^2\\ \\ \\A_{\triangle MNI}=\dfrac{1}{2}\cdot MN\cdot NI\cdot \sin 120^{\circ}=\dfrac{1}{2}\cdot 3\cdot 8\cdot \dfrac{\sqrt{3}}{2}=6\sqrt{3}\ un^2\\ \\ \\$

2. Note that

$A_{\triangle IJK}=A_{\triangle IAK}=\dfrac{3\sqrt{3}}{2}\ un^2 \\ \\ \\A_{\triangle KLM}=A_{\triangle KAM}=4\sqrt{3}\ un^2 \\ \\ \\A_{\triangle MNI}=A_{\triangle MAI}=6\sqrt{3}\ un^2$

3. The area of hexagon IJKLMN is the sum of the area of all triangles:

$A_{IJKLMN}=2\cdot \left(\dfrac{3\sqrt{3}}{2}+4\sqrt{3}+6\sqrt{3}\right)=23\sqrt{3}\ un^2$

Another way to solve is to find the area of triangle KIM be Heorn's fomula, where all sides KI, KM and IM can be calculated using cosine theorem.

7 0

2 years ago

Which expression is equivalent to -3(y-5) A. -3y-4 B -3y+4 C. -3y-12 D -3y+12

ankoles [38]

Answer:

neither when you multiply them you get -3y+15 not 12

hope this helps

have a good day :)

Step-by-step explanation:

3 0

3 years ago

-20a -8 + 12b is ? what is the answer?

Ilia_Sergeevich [38]

Answer:

4(-5a + 3b - 2)

Step-by-step explanation:

Aside from changing the order of the terms so that the "a" term comes first and the "b" term second, there's nothing you can do with this expression -20a -8 + 12b. But notice that 4 is a factor common to all three terms, and therefore it can be factored out:

Rearranging the terms, we get

-20a + 12b - 8 = 4(-5a + 3b - 2)

7 0

2 years ago