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3 years ago

Which inequality shows twelve times the sum of three plus c is greater than 27?

1 answer:

7 0

Hello!

You can break this down

12 times the sum of 3 and c

This can be written as 12(3 + c)

is greater than 27

12( 3 + c) > 27

This can be simplified to 36 + 12c > 27

The answer is 12(3 + c) > 27 or 36 + 12c > 27

Hope this helps!

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The difference of three times a number and 1 is the same as twice the number find the number

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Lisa wants to measure the height of a tree. She walks exactly 50 feet from the base of the tree and looks

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2 years ago

What fractions are equivalent to 9/18

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3 years ago

Read 2 more answers

Two cyclists, Alan and Brian, are racing around oval track of length 450m on the same direction simultaneously from the same poi

skelet666 [1.2K]

Answer:

Alan: 200 m/min

Brian: 150 m/min

Step-by-step explanation:

Given : Two cyclists, Alan and Brian, are racing around oval track of length 450m on the same direction simultaneously from the same point. Alan races around the track in 45 seconds before Brian does and overtakes him every 9 minutes.

To find : What are their rates, in meters per minute?

Solution :

Let n represent the number of laps that Alan completes in 9 minutes.

Then n-1 is the number of laps Brian completes.

45 seconds = 3/4 minutes.

The difference in their lap times in minutes per lap is

$\frac{9}{(n -1)}-\frac{9}{n} =\frac{3}{4}$

Solving the equation we get,

$\frac{9n-9n+9}{n(n -1)} =\frac{3}{4}$

$9\times 4=3\times n(n -1)$

$36=3\times n(n -1)$

$n^2-n-12=0$

$n^2-4n+3n-12=0$

$n(n-4)+3(n-4)=0$

$(n-4)(n+3)=0$

$n=4,-3$

Neglecting n=-3

So, n=4

Then Alan's speed in m/min is

$S=\frac{D}{T}$

$S_a=\frac{4\times 450}{9}$

$S_a=200 m/min$

Brian completes 3 laps in that 9-minute time, so his rate is

$S_b=\frac{3\times 450}{9}$

$S_b=150 m/min$

Therefore, Alan: 200 m/min

Brian: 150 m/min

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3 years ago

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Answer:

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