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Tems11 [23]
3 years ago
5

A millimeter is 0.001 of a meter how many millimeters are there in 7 meters

Mathematics
2 answers:
yawa3891 [41]3 years ago
7 0
\frac{1000 \, mm}{1 \, m} \cdot \frac{7}{7} = \frac{7000 \, mm}{7 \, m}

Therefore, there are 7000 millimeters in seven meters.
OlgaM077 [116]3 years ago
5 0
The answer is 7000 millimeters :3, hope this helps

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The distance between two locations, A and B is calculated using a third location C at a distance of 15 miles from
Rufina [12.5K]
<h3>Answer:  approximately 6.3 miles</h3>

=================================================

Explanation:

See the diagram below. The two given angles B = 105 and C = 20 are used to help find angle A

A+B+C = 180

A+105+20 = 180

A+125 = 180

A = 180-125

A = 55

Then we use the law of sines to find the side length c

sin(A)/a = sin(C)/c

sin(55)/15 = sin(20)/c

c*sin(55) = 15*sin(20) ... cross multiply

c = 15*sin(20)/sin(55)  .... divided both sides by sin(55)

c = 6.26294249724791 .... value is approximate

c = 6.3 ....... rounding to one decimal place

5 0
3 years ago
This is a 10 point question i need help
Bess [88]
It’s B because they both equal each other I would explain more but I’m in class but the answer is definitely B
4 0
3 years ago
136/50<br> as a percentage?
aleksandrvk [35]

Answer: 272%

Step-by-step explanation: To write 136/50 as a percent have to remember that 1 equal 100% and that what you need to do is just to multiply the number by 100 and add at the end symbol % .

136/50 * 100 = 2.72 * 100 = 272%

And finally we have:

136/50 as a percent equals 272%

4 0
3 years ago
Read 2 more answers
Have Retirement Benefits
charle [14.2K]

Answer:

(a) The probability of the intersection of events "man" and "yes" is 0.55.

(b) The probability of the intersection of events "no" and "man" is 0.10.

(c) The probability of the union of events "woman" or "no" is 0.45.

Step-by-step explanation:

The information provided is:

             Yes    No   Total

Men       275   50     325

Women  150   25      175

Total      425   75      500

(a)

Compute the probability that a randomly selected employee is a man and a has retirement benefits as follows:

P(M\cap Y)=\frac{n(M\cap Y)}{N}=\frac{275}{500}=0.55

Thus, the probability of the intersection of events "man" and "yes" is 0.55.

(b)

Compute the probability that a randomly selected employee does not have retirement benefits and is a man as follows:

P(N\cap M)=\frac{n(N\cap M)}{N}=\frac{50}{500}=0.10

Thus, the probability of the intersection of events "no" and "man" is 0.10.

(c)

Compute the probability that a randomly selected employee is a woman or has no retirement benefits as follows:

P(W\cup N)=P(W)+P(N)-P(W\cap N)=\frac{175}{500}+\frac{75}{500}-\frac{25}{500}=0.45

Thus, the probability of the union of events "woman" or "no" is 0.45.

5 0
3 years ago
How do I simplify the square root: 7 times the square root of 81
DENIUS [597]
7\cdot\sqrt{81}=7\cdot\sqrt{9\cdot9}=7\cdot9=\boxed{63}
7 0
3 years ago
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