Answer:
a) All males will have dark wings, all females will have light wings. See attachment
b) Males - 50:50 dark:light, females, 100% dark wings
Explanation:
The ZW sex determination system is different from the XY sex determination system. Females are ZW, whereas males are ZZ (in contrast to XY system where females have two of the same chromosome [XX] and males have two different ones [XY]).
a) The potential genotypes of the F1 are shown in attachment. This shows that all males will have dark wings (Ll) (all heterozygous) and all females will have light wings (l) (all will inherit l allele from father)
b) The potential genotypes of the F2 are shown in attachment. This shows that 50% of the males will have light wings (Ll), and 50% will have dark wings (ll). All of the females will have dark wings (L).
the test tube will be most likely the one with yellowish color.
This happen because of the respiration process between the snail and Elodea. Actually, this will heavily affected by the control factors. The more elodea that exist in the incubation, the lower the amount of CO2 would be,
I believe Enthalpy is the scientific term for the changes. The specific changes each item listed undergoes is hard to say correctly without knowing the options. Could you list the answers to choose from so I can get a better understanding of what they want in the answer?