Answer:
The values of
so that
have vertical asymptotes are
,
,
,
,
.
Step-by-step explanation:
The function cosecant is the reciprocal of the function sine and vertical asymptotes are located at values of
so that function cosecant becomes undefined, that is, when function sine is zero, whose periodicity is
. Then, the vertical asymptotes associated with function cosecant are located in the values of
of the form:
, 
In other words, the values of
so that
have vertical asymptotes are
,
,
,
,
.
The image is (-6, 3)
Hope it helps!
Answer: 9cm
Step-by-step explanation:
The circumference of a circle is given as: = 2πr
where,
π = 3.142
r = radius = unknown
Since circumference = 56.52cm, we'll slot it into the formula which will be:
Circumference = 2πr
2πr = 56.52
2 × 3.142 × r = 56.52
6.284r = 56.52
r = 56.52 / 6.284
r = 8.99
r = 9cm approximately
Answer:
- (x + 10)² + (y + 4)² = 232
Step-by-step explanation:
<h3>Given </h3>
- Center = (-10, -4)
- Point on circle = (4, 2)
<h3>To find </h3>
<h3>Solution</h3>
<u>Remember the standard equation of circle:</u>
- (x - h)² + (y - k)² = r², where (h, k) is the center and r is radius
<u>We have</u>
Use distance formula (Pythagorean theorem) to work out the length of the radius. We know that radius is the distance from the center to any point on the circle.
<u>Here we are finding the distance between points (-10, -4) and (4, 2)</u>
- r² = (-10 - 4)² + (-4 - 2)²
- r² = 14² + 6²
- r² = 232
<u>So the equation is:</u>
- (x + 10)² + (y + 4)² = 232