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matrenka [14]
3 years ago
12

HELPPPPPPPPPPP!!!!!!!!!!!!!

Mathematics
1 answer:
Molodets [167]3 years ago
3 0
Choice A is false. There are 15% of freshman in her BIO class, but there are 35% of her total students in it.
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12 ft<br> 8 ft<br> 8 ft<br> Find the area of the kite.
mamaluj [8]
I’m not sure but I’m guessing it could be 8 ft
4 0
3 years ago
Read 2 more answers
The credit remaining on a phone card (in dollors) is a linear function of the total calling trime made with the card ( in minute
KATRIN_1 [288]

After 85 minutes of calls, there are $27.25 left on the card.

<h3>What is the remaining credit after 85 minutes of calls?</h3>

A linear equation in slope-intercept form is:

y = a*x + b

Where a is the slope.

If the line passes through two points (x₁, y₁) and (x₂, y₂) the slope is:

a = \frac{y_2 - y_1}{x_2 - x_1}

In this case, we know that the line passes through the points (22, 36.7) and (52, 32,20)

(points of the form (time, dollars)).

So the slope is:

a = \frac{32.2 - 36.7}{52 -22} = -0.15

The linear equation is then:

y = -0.15*x + b

To find the value of b, we use the point (22. 36.7)

36.7 = -0.15*22 + b

36.7 + 0.15*22 = b = 40

Then the linear equation is:

y = -0.15*x +40

The amount remaining in the credit card after 85 minutes is given by evaluating the above equation in x = 85.

y = -0.15*85 + 40 = 27.25

This means that after 85 minutes of calls, there are $27.25 left on the card.

If you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ1

7 0
2 years ago
Please helpp I would really appreciate it.
fiasKO [112]
I got 3/8, hope this helps.
5 0
3 years ago
A parabola can be drawn given a focus of (5, -3) and a directrix of y=1. Write the equation of the parabola in any form.
Anna71 [15]

Answer:

(x²-10x+33)/(-8) = y

Step-by-step explanation:

The distance between any point on a parabola from both its focus and directrix are the same.

Let's say we have a point (x,y) on the parabola. We can then say that using the distance formula,

\sqrt{(x-5)^2+(y-(-3))^2}is the distance between (x,y) and the focus. Similarly, the distance between (x,y) and the directrix is |y-1| (I use absolute value here because distance is always positive). We can find this equation by taking the shortest distance from the point to the line. Because the closest point to the line will be the same x value as the point itself, the distance is simply the distance between the y value of the point and the y value of the directrix.

Equating the two equations given, we have

\sqrt{(x-5)^2+(y-(-3))^2} = |y-1|

square both sides to get

(x-5)²+(y+3)²=(y-1)²

expand the y components

(x-5)² + y²+6y+9 = y²-2y+1

subtract y²+6y+9 from both sides

(x-5)² = -8y - 8

expand the x components

x²-10x+25 = -8y - 8

add 8 to both sides to isolate the -8y

x²-10x+33 = -8y

divide both sides by -8 to isolate y

(x²-10x+33)/(-8) = y

6 0
2 years ago
What is the radius of convergence of the maclaurin series (2x)/(1+x^2)?
kramer
To solve this problem you must apply the proccedure shown below:
 1. You have to find the radius <span>of convergence of the following Maclaurin series:
 </span>(2x)/(1+ x^{2} )&#10;
 2. Let's take the denominator and find the roots:
 1+ x^{2} =0
 x^{2} =-1 \\ x= \sqrt{-1} \\ x1=i \\  x2=-i
 3. The roots are x1=i \\ x2=-i and the distance from the origin is 1.
 Therefore, the answer is: 1
7 0
2 years ago
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