Yes it's quadratic because x which is after y is squared
Step-by-step explanation:
![3 + ( - 2) \ast6 \\ = 3 + ( - 2 \times 6) \\ = 3 + ( - 12) \\ = 3 - 12 = - 9](https://tex.z-dn.net/?f=3%20%2B%20%28%20-%202%29%20%5Cast6%20%5C%5C%20%20%3D%203%20%2B%20%28%20-%202%20%5Ctimes%206%29%20%5C%5C%20%20%3D%203%20%2B%20%28%20-%2012%29%20%5C%5C%20%20%3D%203%20-%2012%20%3D%20%20-%209)
Answer:
(13 + x) * (15 + x) = 390ft²
18.8 feets ; 20.8 feets
Step-by-step explanation:
Given that:
Initial dimension of patio :
Length (L) = 13 feets
Width ( W) = 15 feets
Initial Area of rectangle :
Length * width = 13 * 15 = 195 feets²
To double the initial area of rectangle :
2 * 195 ft² = 390 ft²
Hence, area of proposed patio = 390ft²
Area of proposed patio:
(13 + x) * (15 + x) = 390ft²
195 + 13x + 15x + x² = 390
x² + 18x - 195 = 0
Using the quadratic equation solver:
X = - 33.77 = - 33.8 or
X = 5.77 = 5.8
X cannot be negative,
Hence, x = 5.8
Length and width of new patio:
Length = 13 + x = 13 + 5.8 = 18.8 feets
Width = 15 + x = 15 + 5.8 = 20.8 feets
Answer:
![\frac{x + 2}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%2B%202%7D%7B3%7D%20)
Step-by-step explanation:
Replace y with f(x).
![y = 3x - 2](https://tex.z-dn.net/?f=y%20%3D%203x%20-%202)
Swap x and y and solve for y
![x = 3y - 2](https://tex.z-dn.net/?f=x%20%3D%203y%20-%202)
![x + 2 = 3y](https://tex.z-dn.net/?f=x%20%2B%202%20%3D%203y)
![\frac{x + 2}{3} = y](https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%20%2B%202%7D%7B3%7D%20%20%3D%20y)