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Lubov Fominskaja [6]
4 years ago
5

In triangle ABC, a = 12, _ B= 25°, and C= 45°. Find b.

Mathematics
1 answer:
dusya [7]4 years ago
4 0

The value of b is 5.4

Explanation:

Given that ABC is a triangle.

It is also given that a=12 , \angle B=25^{\circ} and \angle C=45^{\circ

We need to find the value of b.

The value of b can be determined using the law of sine formula, which is given by

\frac{a}{sin A} =\frac{b}{sin B} =\frac{c}{sin C}

First, we shall find the angle of A.

Since, ABC is a triangle and all the angles in a triangle add up to 180°

Thus, we have,

\angle A+\angle B+\angle C=180

  \angle A+25+45=180

          \angle A+70=180

                  \angle A=110^{\circ}

Thus, the value of angle A is 110°

Let us substitute these values in the law of sine formula.

Hence, we get,

\frac{12}{sin \ 110^{\circ}} =\frac{b}{sin \ 25^{\circ}}

Simplifying, we get,

\frac{12}{0.9397} =\frac{b}{0.423}

Multiplying both sides of the equation by 0.423, we get,

\frac{12\times 0.423}{0.9397} =b

Simplifying, we get,

\frac{0.5076}{0.9397} =b

Dividing, we have,

5.4=b

Thus, the value of b is 5.4

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How many solutions can be found for this set of linear equationsy=7(x+2)y=7x+14
Bogdan [553]

Answer:

Infinite solutions

Step-by-step explanation:

The two equations are the same, so therefore, any value of x will result in an output that belongs to both lines, if you understand what I mean.

Hope this helps :)

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2 years ago
Item cost $430 before taxes and the sales tax is $38.70 find a sales tax
natulia [17]

Answer:

sales tax= 9 %

Step-by-step explanation:

sales tax= cost x %tax

38.70 = 430 x %tax

%tax = 38.7/430 = 0.09 = 9 %

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8 0
4 years ago
Which points are solutions to the linear inequality y &lt; 0.5x +<br> 2? Select three options.
Ymorist [56]

Answer:

Options (1), (3), and (5)

Step-by-step explanation:

In the figure attached,

An inequality has been graphed and the shaded region shows its solutions.

Inequality : y < 0.5x + 2

If the given points in the options lie in the shaded region, point will satisfy the inequality.

For (3, -2)

-2 < 0.5(3) + 2

-2 < 3.5 [True]

Therefore, (3, -2) point is the solution.

For (-2, 1)

1 < 0.5(-2) + 2

1 < -1 + 2

1 < 1 [Not true]

Therefore, (-2, 1) is not the solution.

For (-1, -2)

-2 < 0.5(-1) + 2

-2 < 1.5 [True]

Therefore, (-1, -2) is the solution.

For (-1, 2)

2 < 0.5(-1) +2

2 < 1.5 [Not True]

Therefore, (-1, 2) is not the solution.

For (1, -2)

-2 < 0.5(1) + 2

-2 < 2.5 [True]

Therefore, (1, -2) is the solution.

Options (1), (3) and (5) will be the answer.

7 0
4 years ago
Please help me with this
FrozenT [24]
See you Need to round it so it is c=-4
5 0
3 years ago
How to write a polynomial function with rational coefficients in standard form with the given zeros?
Gennadij [26K]
If you have as many zeros (z1, z2,... zn) as the degree of the polynomial function (n), then the function equation is given by:

f(x) = k (x - z1) (x - z2) ··· (x - zn)

where k is a constant. To determine this constant you need additional information (e.g. another point of the function).

You might also have less zeros than the degree of the polynomial, because some of them have a multiplicity greater than 1. Let z1,...,zr be the zeros, and m1,...mr be the multiplicity of each zero, where m1+m2+...+mr=n (we assume the sum of all multiplicities equals the degree of the polynomial). In this case, you can use:

f(x)=k(x-z_1)^{m_1} (x-z_2)^{m_2} \cdots (x-z_r)^{m_r}

Again, you have an undetermined constant factor.

From any of the two expressions above, you have to apply the distributive property to go on to the standard form.

An example: the zeros of a 3-degree polynomial function are -2, 1 and 3. The function equation is of this form:

f(x)=k(x+2)(x-1)(x-3) = k(x^3-2x^2-5x+6)

If you don't have all the zeros, or the sum of multiplicities does not equal the degree of  the polynomial, you have not enough information to write the equation of the function.

4 0
3 years ago
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