Ask question

Ask question

All categories

4 years ago

15

A radio station's signal has a radius of 100 miles. If you drive at a constant speed of 40 miles an hour, nonstop, directly acro

ss the diameter of the signal, how long can you listen to the station before the signal fades?
O 4 hour 14. 13. The difference between two numbers is 25.
The smaller number is 1/6th of the larger number.
What is the value of the smaller number?
0 11 03 O 5 O 2.5 hours O 2 hours O 5 hours 0 10

1 answer:

Lady_Fox [76]4 years ago

7 0

Answer: you can listen radio signal during 5h

Step-by-step explanation: t =d/v=2xradius÷velocity=2x100miles ÷ 40mile/h = 5h

You might be interested in

You have 2.5 pounds of egg whites.

Rufina [12.5K]

Answer:

15

Step-by-step explanation:

38/2.5=15.2

Round it to 15

4 0

4 years ago

Solve x4 - 34x2 = -225

RSB [31]

Answer:

x= -5,5 and -3,3

6 0

3 years ago

Elvera Hilton earns $12 an hour at her job. The hours she worked during each of the last four weeks are shown below

Minchanka [31]

Answer:

12x7 4 times add it up u got the anwser

6 0

2 years ago

Question 4 (1 point)<br> (-7x + 5) - (-82 – 6) =

Keith_Richards [23]

no ye puedo ayudar amigo o amiga

8 0

3 years ago

Find the angle between the given vectors. Round your answer, in degrees, to two decimal places. u=⟨2,−6⟩u=⟨2,−6⟩, v=⟨4,−7⟩

NISA [10]

Answer:

$\theta = 108.29$

Step-by-step explanation:

Given

$u =$

$v =$

Required:

Calculate the angle between u and v

The angle $\theta$ is calculated as thus:

$cos\theta = \frac{u.v}{|u|.|v|}$

For a vector

$A =$

$A = a * b$

$cos\theta = \frac{u.v}{|u|.|v|}$ becomes

$cos\theta = \frac{.}{|u|.|v|}$

$cos\theta = \frac{2*6+4*-7}{|u|.|v|}$

$cos\theta = \frac{12-28}{|u|.|v|}$

$cos\theta = \frac{-16}{|u|.|v|}$

For a vector

$A =$

$|A| = \sqrt{a^2 + b^2}$

So;

$|u| = \sqrt{2^2 + 6^2}$

$|u| = \sqrt{4 + 36}$

$|u| = \sqrt{40}$

$|v| = \sqrt{4^2+(-7)^2}$

$|v| = \sqrt{16+49}$

$|v| = \sqrt{65}$

So:

$cos\theta = \frac{-16}{|u|.|v|}$

$cos\theta = \frac{-16}{\sqrt{40}*\sqrt{65}}$

$cos\theta = \frac{-16}{\sqrt{2600}}$

$cos\theta = \frac{-16}{\sqrt{100*26}}$

$cos\theta = \frac{-16}{10\sqrt{26}}$

$cos\theta = \frac{-8}{5\sqrt{26}}$

Take arccos of both sides

$\theta = cos^{-1}(\frac{-8}{5\sqrt{26}})$

$\theta = cos^{-1}(\frac{-8}{5 * 5.0990})$

$\theta = cos^{-1}(\frac{-8}{25.495})$

$\theta = cos^{-1}(-0.31378701706)$

$\theta = 108.288386087$

<em></em> $\theta = 108.29$ <em> (approximated)</em>

4 0

3 years ago