Any improper fraction would work for this case since they are all greater than 1. For instance 3/2 * 2 would be equal to 3 which is greater than 2.
Answer: 2 real zeros
discriminant: b^2 - 4ac
a = 3, b = -7, and c = 4
so, (-7)^2 - 4(3)(4) = 1
Since the discriminant is positive, there are 2 real zeros, if the discriminant was negative there would be 2 complex zeros, and if the discriminant equaled 0 then there is one real answer
Answer:
B
Step-by-step explanation:
You're passing to the left first and getting back to your side on the right
15 ft
there are 5 squares, each square is 5 square.
The answer is 95
Work
100 - (2)(8) + 11
100 - 16 + 11
84 + 11
= 95
