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pychu [463]
3 years ago
15

The standard form of the equation for a quadratic function is, with he vertex of the graph of the function at the point (p,q). t

he factored form is y=a(x-x1) (x-x2), where x1 and x2 are the x-intercepts of the graph. Express p and q in terms of x1 and x2 by expanding the factored for then completing the square. Please show work.
Mathematics
1 answer:
ludmilkaskok [199]3 years ago
3 0

Answer:

p = ½ (x₁ + x₂)

q = a (x₁x₂ − ¼ (x₁ + x₂)²)

Step-by-step explanation:

y = a (x − x₁) (x − x₂)

Expand:

y = a (x² − x₁x − x₂x + x₁x₂)

y = a (x² − (x₁ + x₂)x + x₁x₂)

Distribute a to the first two terms:

y = a (x² − (x₁ + x₂)x) + ax₁x₂

Complete the square:

y = a (x² − (x₁ + x₂)x + ¼(x₁ + x₂)²) + ax₁x₂ − ¼ a(x₁ + x₂)²

y = a (x − ½ (x₁ + x₂))² + a (x₁x₂ − ¼ (x₁ + x₂)²)

Therefore:

p = ½ (x₁ + x₂)

q = a (x₁x₂ − ¼ (x₁ + x₂)²)

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The function, f(x) = –2x2 + x + 5, is in standard form. The quadratic equation is 0 = –2x2 + x + 5, where a = –2, b = 1, and c =
avanturin [10]
Given:

The function, f(x) = -2x^2 + x + 5

Quadratic equation: 0 = -2x^2 + x +5
where a = -2
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The discriminate b^2 - 4ac = 41

To solve for the zeros of the quadratic function, use this formula:

x = ( -b +-√ (b^2 - 4ac) ) / 2a

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3 years ago
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The larger of two consecutive integers is 10 more than 4 times the smaller. Find the integers.
nevsk [136]

Answer:

-2 and -3

Step-by-step explanation:

Let L represent the large integer and S represent the smaller integer

Given  Large Integer = 10 + 4 times Smaller Integer

Mathematically:

L = 10 + 4S -------eq 1

It is also given that the integers are consecutive,

hence L = S + 1------ eq2

Now we can solve a system of equations by substitution.

Substitute eq 2 into eq 1

S + 1 = 10 + 4S    (subtract 1 from both sides)

S = 10 - 1 + 4S

S = 9 + 4S  (subtract 4S from both sides)

S - 4S = 9

-3S = 9 (divide both sides by -3)

S = 9 / (-3) = -3  (answer)

form equation 2,

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3 0
3 years ago
A circle with radius of 4 cm sits inside a circle with radius of 11 cm.
kap26 [50]

The area of the shaded region = 330 sq cm

Step-by-step explanation:

Given,

The radius of small circle (r) = 4 cm

The radius of large circle (R) = 11 cm

To find the shaded region

Formula

The area of circle of radius r = πr^{2} sq cm

So, The radius of the small circle = π×4^{2} sq cm = 16π sq cm

The radius of the large circle = π×11^{2} sq cm = 121π sq cm

Hence the area of the shaded region = 121π-16π sq cm

= 105π sq cm

= 105 × \frac{22}{7} sq cm = 330 sq cm

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3 years ago
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