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stepan [7]
3 years ago
7

If the slope of y=2x+5 is changed to -2, how does the graph change?

Mathematics
1 answer:
Anon25 [30]3 years ago
4 0
Don’t know can’t tell you
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The midpoint of JK is M(7, 9). One endpoint is J(5, 8). Find the coordinates of the other endpoint K.
Yakvenalex [24]

Step-by-step explanation:

(7,9)and (5,8)

x1,y1 x,y

now

x=(x1 + x2)divide by 2

now putting the value

5 = (7+ x2) by 2

2 is in divide then get the 2 in right side with 5 in muntiply form

5×2=7+x2

10=7+x2

10 - 7=x2

x2=3

using the same process do it

y=(y1+y2) by 2

7 0
2 years ago
Read 2 more answers
Jamal wants to install a rectangular 2025 cm² window in his garden shed. That area of window comes in several length/width combi
frosja888 [35]

Answer:

The ideal size will be a 45cmx45cm square, giving you a perimeter of 180cm.

Step-by-step explanation:

The shortcut answer here is that the square will always be the most efficient rectangle for border to area, so the sides should be the square root of 2025 cm, or 45 cm each, giving you a total of 180 minimum perimeter.

The full solution is to express the perimeter as a function of the length and width, define either length or width as a function of the other, take the entire expression's derivative and solve for zero.  Let's do it:

So first the area:

2025 = wl

l = 2025 / w

Now the sides:

p = 2w + 2l\\p = 2w + 2(2025 / w)\\p = 2w + 4050 / w

Then we can take its derivative with respect to w

p = 2w + 4050\frac{1}{w}\\\frac{dp}{dw} = 2 + 4050\frac{-1}{w^2}\\

Now we can set the derivative to zero, and solve for w:

\frac{dp}{dw} = 2 + 4050\frac{-1}{w^2}\\0 = 2 + \frac{-4050}{w^2}\\-2 =  \frac{-4050}{w^2}\\2w^2 = 4050\\w^2 = 2025\\w = \sqrt{2025}\\w = 45

So the width being 45, we can get the length by dividing the area by that amount, which of course is also 45.

3 0
3 years ago
Line m passes through points (2,-5) and (4,-3). Line n passes through points (-4,-8) and (-6,-6). Are lined m and n perpendicula
DENIUS [597]
The answer for that is C
4 0
3 years ago
Please help me with this problem!
mina [271]

Answer:

Step-by-step explanation:

The diagram shows lines passing through the points of two equations.

We will determine the points through which the lines pass through on the graphs.

Looking at the line on the right hand side of the graph, the slope is

(y2-y1)/x(2-x1) where

y2= 0, y1 = 4

x2 = 3, x1=0

Slope, m = (0-4)/3-0

Slope = -4/3

Recall the equation of a straight line is y = mx + c

Where c is the intercept.

So the equation is y

y = -4x/3 + 4

Looking at the line on the left hand side of the graph, the slope is

(y2-y1)/x(2-x1) where

y2= 0, y1 = 2

x2 = -1, x1 =0

Slope, m = (0-2)/-1-0

Slope = -2/-1 = 2

Applying equation of a straight line is y = mx + c

The equation

y = 2x + 2

So the equations are

-4x/3 + 4. If x lesser than or equal 0

2x + 2. If x greater than 0

4 0
3 years ago
Which statement best describes how to determine whether f(x) = x4 – x3 is an even function?
Setler79 [48]
It would equal x=0 so no
3 0
4 years ago
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