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Mumz [18]
3 years ago
13

What is the approximate circumference of the circle shown below

Mathematics
1 answer:
Anna [14]3 years ago
7 0

Answer: 38.3

Step-by-step explanation:

c=2pir

r=6.1 (half of diameter)

c=38.3 cm

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Please I really need help:
Kobotan [32]
Hi there

The answer is
b.) y=8,000(1.14)^x

Good luck!
6 0
3 years ago
Read 2 more answers
Which answer lists these numbers in order from least to greatest? -24.8,142,1.13,-2.81,24.1
Vadim26 [7]
The answer is a.  -24.8, -2.81, 1.13, -2.81, 24.1

This is because the larger a negative number is, the lower its value is.  So, when putting numbers from least to greatest, you put the largest negative numbers first, and then work your way up to zero.  Then, you start counting upwards with your positive numbers.
8 0
3 years ago
What is the product of the two integer values for $x$ for which $|x^2 - 16|$ is a prime number?
Nana76 [90]

Answer:

-9

Step-by-step explanation:

x² -16 = (x -4)(x +4)

This magnitude of this product can only be prime if one of the factors is ±1. Any other integer value of x will produce a composite number (or zero).

... For x-4 = ±1, x = 3 or 5

... For x+4 = ±1, x = -3 or -5

The values of x that are ±3 both give |x²-16| = 7, a prime.

The values of x that are ±5 both give |x²-16| = 9, not a prime.

The two values of x that are of interest are x=-3 and x=3. Their product is ...

... (-3)·(3) = -9

8 0
3 years ago
Find the height of a triangular prism with a base length of 10 yards, a base height of 20 yards, and a volume of 600 cubic yards
Artemon [7]
The volume of the triangular prism is the Area of the base times the height
the area of the base is:
\frac{ab}{2}
and the volume is:
V=(\frac{ba}{2})h

now b=10 yards,  a=20 yards, and V=600 yards^3
we clean the height 

h=\frac{2V}{ab}=\frac{2\cdot 600}{10\cdot 20} = 6


the answer is height = 6 yards


8 0
3 years ago
If P (A)=0.84, P(B)=0.76 AND P(A OR B) =0.9, THEN P (A and B)=0.7
STatiana [176]
Sorry i tried to figure it out but i could not seem to get the answer. :(
4 0
3 years ago
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