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Artyom0805 [142]
3 years ago
6

Evaluate the series

Mathematics
1 answer:
lesantik [10]3 years ago
8 0
S=\displaystyle\sum_{n=1}^7\left(\frac14\right)^n

\displaystyle S=\frac14+\left(\frac14\right)^2+\cdots+\left(\frac14\right)^7
\displaystyle\frac14S=\left(\frac14\right)^2+\left(\frac14\right)^3+\cdots+\left(\frac14\right)^8
\displaystyle S-\frac14S=\frac14+\left(\left(\frac14\right)^2-\left(\frac14\right)^2\right)+\cdots+\left(\left(\frac14\right)^7-\left(\frac14\right)^7\right)-\left(\frac14\right)^8
\displaystyle\frac34S=\frac14-\left(\frac14\right)^8
\displaystyle S=\frac{\frac14-\left(\frac14\right)^8}{\frac34}=\frac{5461}{16384}
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Option A)   Inside the circle

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The radius is equal to the distance from the center to any point on the circle

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d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

we have

A(-5,-8),M(-1,-3)

substitute the values

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Find the distance from the center to point V

we know that

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If the distance from the center to point V is greater than the radius, then the point V lie outside the circle

we have

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d=\sqrt{(-6+8)^{2}+(-11+5)^{2}}

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