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Marianna [84]
3 years ago
13

Sabrina has designed a rectangular painting that measures 65 feet in length and 30 feet in width. Alfred has also designed a rec

tangular painting, but it measures x feet shorter on each side. When x = 3, what is the area of Alfred's painting?
Mathematics
1 answer:
liubo4ka [24]3 years ago
3 0

Answer:

1674 ft²

Step-by-step explanation:

Area S = 65*30

Area A = (65 - x)(30 - x) = (65 - 3)(30 - 3) = 62*27= 1674 ft²

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