Answer:
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Step-by-step explanation:
Answer:
The value of x is 200 in the equation 1/5x - 2/3y = 30, when y = 15
Step-by-step explanation:
<u>Given</u>
equation: x - 2/3y = 30
when y = 15
<em>Plug in y:</em>
1/5x - 2/3(15) = 30
1/5x - 10 = 30
<em>add</em> 10 to both sides,
1/5x - 10 + 10 = 30 + 10
1/5x = 40
<em>multiply</em> both sides by 5
1/5x * 5= 40 * 5
x = 200
Given equation of the Circle is ,
And we need to tell that whether the point (-4,2) lies inside or outside the circle. On converting the equation into Standard form and determinimg the centre of the circle as ,
Here we can say that ,
• <u>Radius</u> = 5 units
• <u>Centre </u> = (0,0)
<u>Finding</u><u> </u><u>distance</u><u> between</u><u> </u><u>the </u><u>two </u><u>points</u><u> </u><u>:</u><u>-</u><u> </u>
- Here we can see that the distance of point from centre is less than the radius.
<u>Hence </u><u>the</u><u> </u><u>point</u><u> </u><u>lies </u><u>within</u><u> </u><u>the </u><u>circle</u><u> </u><u>.</u>
Answer:
7
Step-by-step explanation:
This is a Poisson distribution problem with the formula;
P(x;μ) = (e^(-μ)) × (μ^(x))/x!
We are told that the grocer sells three of a certain article per week. Thus;
μ = 3
Now, we want to find out How many of these should he have in stock so that the chance of his running out within a week is less than 0.01.
This means;
P(X > k) < 0.01
This can be rewritten as;
P(X ≤ k) < 0.99
Let's try x = 8
P(8;3) = (e^(-3)) × (3^(8))/8!
P(8;3) = 0.008
But; P(X ≤ 8) = 1 - 0.008 = 0.992
This is more than 0.99 and thus is not the answer
Let's try x = 7
P(7;3) = (e^(-3)) × (3^(7))/7!
P(7;3) = 0.022
But; P(X ≤ 7) = 1 - 0.022 = 0.978
Thus is less than 0.99.
Thus, stock should be 7