All categories

2 years ago

...............................help!!!

Mathematics

2 answers:

Ray Of Light [21]2 years ago

5 0

Answer:

Step-by-step explanation:

Sophie [7]2 years ago

5 0

Aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa the answers A

You might be interested in

The whole numbers from 10-12 are paired with their factors explain why this pairing doesnt describe a function

myrzilka [38]

Answer:

As given whole numbers from 10 - 12 are paired with their factors.

factor of ,10=1,2,5,10 → (10,1),(10,2),(10,5)(10,10)

factor of 11=1, 11 → (11,1),(11,11)

factor of 12=1,2,3,4,6,12→ (12,1),(12,2),(12,3),(12,4),(12,6),(12,12)

As we know for an ordered pair to be function Every element in the domain must have a unique image, i.e it can't have more than one image.

→ As element 10, have four images,which are 1,2,5,10 so it can,t be a function.

Similarly element 11 have two images 1,11 so it can't be a function.

Element 12 have six images 1,2,3,4,6,12, so it also can't be written as function.

8 0

3 years ago

What is the angle of rotation of the figure?

tamaranim1 [39]

The rotation is were you keep one point at the same spot and move the others

5 0

3 years ago

The math club wants to order t-shirts to recognize students who improved their performances in algebra I. Hot shirt charges $12.

horsena [70]

Answer:

1000

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

If 14x = ^13√14, what value of x makes this equation true?

Andrews [41]

The value of x is 1/13 (4th choice)

Step-by-step explanation:

${a}^{ \frac{m}{n} } = \sqrt[n]{ {a}^{m} }$

If 14^x = ¹³√14, what value of x makes this equation true?

$\sqrt[13]{14} = {14}^{x} \\ \sqrt[13]{14} = {14}^{ \frac{1}{13} }$

So, the value of x is 1/13 (4th choice)

Hope it helpful and useful :)

6 0

3 years ago

Help meee I’ll give 10 pts and brainliest!!!

crimeas [40]

Step-by-step explanation:

i) $\overline{AB} = \sqrt{(x_A - x_B)^2 + (y_A - y_B)^2}$

$\:\:\:\:\:\:\:=\sqrt{(2)^2 + (12)^2} = 12.3$

ii) $m = \dfrac{y_A - y_B}{x_A - x_B} = \dfrac{-12}{2} = -6$

iii) $(\overline{x},\:\overline{y}) = \left(\dfrac{x_A + x_B}{2},\:\dfrac{y_A + y_B}{2}\right)$

$\:\:\:\:\:\:\:=(3,\:-2)$

7 0

3 years ago