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Vera_Pavlovna [14]
3 years ago
8

The volume of a cylinder of radius 3r and height 6r is given by TT(3r)2(6r). Simplify the expression.

Mathematics
1 answer:
OLga [1]3 years ago
6 0

Answer: \pi 36r^{2}

Step-by-step explanation:

ALRIGHT ARE YOU READY FOR EPIC MATH TIME?

because i know i am. so lets get this bread.

WATCH: we have \pi (3r)2(6r)

interesting... that first character is called pi. maybe i should have said, "lets get this pi".

so now lets do some algebra. i am going to work from right to left. lets multiply 6r by 2. that gives us 12r. now we have... \pi (3r)(12r)

WE ARE MAKING EPIC PROGRESS, AREN'T WE?

lets multiply 12r by 3r. then we have....

\pi 36r^{2}

notice how i multiplied 12 by 3 and also r by r (which gives 36 and r^{2} respectively)

so your simplified expression is: \pi 36r^{2}

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How many three digit numbers have digits whose sum is greater than 2?
LenaWriter [7]

Answer:

896

Step-by-step explanation:

Let's talk first about how many 3 digit numbers there are. The first 3 digit number is 100 and the last is 999. So there are 999-100+1 numbers that are 3 digits long. That simplifies to 900.

Now let's find how many of those have a sum for the digits being 1, then 2 ? Then take that sum away from the 900 to see how many 3 digit numbers have the sum of their digits being more than 2.

3 digit numbers with sum of 1:

The first and only number is 100 since 1+0+0=1.

We can't include 010 or 001 because these aren't really three digits long.

3 digit numbers with sum of 2:

The first number is 101 since 1+0+1=2.

The second number is 110 since 1+1+0=2.

The third number is 200 since 2+0+0=2.

That's the last of those. We could only use 0,1, and 2 here.... Anything with a 3 in it would give us something larger than or equal to 3.

So there are 900-1-3 numbers who are 3 digits long and whose sum of digits is greater than 2.

This answer simplifies to 896.

3 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP
Igoryamba

Answer:

∠1 - 40°

Step-by-step explanation:

∠1 - 40°

b/c it's a right triangle and we have two angles given, 50° and 90°. Add them and subtract by 180° and get 40°.

∠2 - 140°

b/c an exterior (outside) angle is equal to the two most isolated / farthest angles added. The two most is angles are 105° and 35°, add them and get 140°.

∠3 - 40°

b/c ∠'s 1 and 3 are vertical angles meaning they're equal so since ∠1 is 40°, so is ∠3.

∠4 -

b/c ∠' s 2 and 4 are vertical angles meaning they're equal so since ∠2 is 140°, so is ∠4.

∠5 - 35°

b/c we have two angles, 105° and 40°. Add them and subtract by 180° and get 35°.

~~

I hope that helps you out!!

5 0
3 years ago
I’ll give Brainly for helping
Vanyuwa [196]

Answer: 16

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Can someone please help me with this? it’s algebra 2
riadik2000 [5.3K]
I am big pp lol xD hxyjdrh
8 0
3 years ago
Read 2 more answers
I’ll give you all my love and affection if you help me with this ASAP PLEASE ;)
guapka [62]
Answer: (12,0)


Steps:

First, put the equation in slope-intercept form.

y=mx+b

1.5x + 4.5y =18

Subtract 1.5x from both sides.

4.5y =-1.5x +18

Divide both sides by 4.5 to isolate y.

y = -1/3x + 4


Then replace y with 0 because the point for the x-intercept is exactly on the x-axis so the y=0.

0 = -1/3x + 4

Subtract 4 from both sides

-4 = -1/3x

Divide both sides by -1/3 to isolate the x

12=x
4 0
3 years ago
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