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Vera_Pavlovna [14]
3 years ago
8

The volume of a cylinder of radius 3r and height 6r is given by TT(3r)2(6r). Simplify the expression.

Mathematics
1 answer:
OLga [1]3 years ago
6 0

Answer: \pi 36r^{2}

Step-by-step explanation:

ALRIGHT ARE YOU READY FOR EPIC MATH TIME?

because i know i am. so lets get this bread.

WATCH: we have \pi (3r)2(6r)

interesting... that first character is called pi. maybe i should have said, "lets get this pi".

so now lets do some algebra. i am going to work from right to left. lets multiply 6r by 2. that gives us 12r. now we have... \pi (3r)(12r)

WE ARE MAKING EPIC PROGRESS, AREN'T WE?

lets multiply 12r by 3r. then we have....

\pi 36r^{2}

notice how i multiplied 12 by 3 and also r by r (which gives 36 and r^{2} respectively)

so your simplified expression is: \pi 36r^{2}

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Mr. Doyle washed
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Answer:

Mr Doyle washed the most.

4/15 still need to be washed.

Step-by-step explanation:

2/5=6/15  Mr Doyle

1/3=5/15   Son

so Mr Doyle washed the most.

Together they washed 11/15 of the laundry so 4/15 is left to wash.

7 0
2 years ago
BD is the angle bisector of ZABC.
mojhsa [17]

Answer:

B:25°

Step-by-step explanation:

Now \angle ABC gets bisected by BD.

\angle ABD=25^{\circ}

Since, the angle is bisected, this means that the angle is split into two equal parts or the angle is halved.

We know that one of the angles is 25^{\circ} so the other angle has to be 25^{\circ} also.

Hence, the m\angle DBC=25^{\circ}.

6 0
3 years ago
Which are the solutions of the quadratic equation? x2 = –5x – 3 –5, 0 StartFraction negative 5 minus StartRoot 13 EndRoot Over 2
boyakko [2]

<u>Given</u>:

The quadratic equation is x^{2}=-5 x-3

We need to determine the solutions of the quadratic equation.

<u>Solution</u>:

Let us solve the equation to determine the value of x.

Adding both sides of the equation by 5x and 3, we get;

x^{2}+5 x+3=0

The solution of the equation can be determined using quadratic formula.

Thus, we get;

x=\frac{-5 \pm \sqrt{5^{2}-4 \cdot 1 \cdot 3}}{2 \cdot 1}

x=\frac{-5 \pm \sqrt{25-12}}{2 }

x=\frac{-5 \pm \sqrt{13}}{2 }

Thus, the two roots of the equation are x=\frac{-5 + \sqrt{13}}{2 } and x=\frac{-5- \sqrt{13}}{2 }

Hence, the solutions of the equation are x=\frac{-5 + \sqrt{13}}{2 } and x=\frac{-5- \sqrt{13}}{2 }

6 0
3 years ago
Read 2 more answers
1. Multiply 5x by (3x+2) *​
Umnica [9.8K]

Answer:

5x (3x +2)

15x² + 10X

7 0
2 years ago
50 POINTS!! EASY!
frosja888 [35]

9514 1404 393

Answer:

  • y = -16
  • x = 10

Step-by-step explanation:

The direct proportion equation is ...

  y = kx

where k is the constant of proportionality. Here, you're told k=-2, so the equation is ...

  y = -2x

For x=8, the value of y is ...

  y = -2(8) = -16 . . . . . do the multiplication

For y = -20, the value of x is ...

  -20 = -2x

  10 = x . . . . . . . . . divide both sides by -2

3 0
3 years ago
Read 2 more answers
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