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Paladinen [302]
3 years ago
5

I don't get this probken

Mathematics
2 answers:
alexira [117]3 years ago
7 0
The last number is in parenthesis because it's a negative: nevermind that for now.
What you want to do is 29-4.37 FIRST.
That gets you:
24.63. NOW you want to subtract the last number, because adding a negative = subtracting a positive.
24.63 - 5.68
Solve:
18.95
jarptica [38.1K]3 years ago
3 0
First, do 29-4.37. Then take that number and add it with -5.68 and that will be your answer.
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Answer:top left corner

Step-by-step explanation:

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3 years ago
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Find the area of the region bounded by the x-axis and the curves y=7sin(x) and y=7 cos(x) where x∈[0,(π/2)]
castortr0y [4]
To calculate the area between both curves, we must calculate the following integrals:
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 int a-b: integral from a to b
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 int 0-π / 2 [(7 cos (x) -7sin (x))] dx = int 0 -π / 2 [(7 cos (x)] dx + int 0-π / 2 [-7sin (x) )] dx
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 answer
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5 0
3 years ago
1/2[8-x]=8-x/2 please help me
Tom [10]
I came up with 4+x/2 Idk if you have to go smaller
5 0
3 years ago
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ASAP! what is 5x^2-18x+9????
netineya [11]

Answer:

(x - 3)(5x - 3)

Step-by-step explanation:

Assuming you require the expression to be factorised.

Given

5x² - 18x + 9

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 5 × 9 = 45 and sum = - 18

The factors are - 15 and - 3

Use these factors to split the x- term

5x² - 15x - 3x + 9 ( factor the first/second and third/fourth terms )

= 5x(x - 3) - 3(x - 3) ← factor out (x - 3) from each term

= (x - 3)(5x - 3) ← in factored form

7 0
4 years ago
Read 2 more answers
El area de un triangulo es de 432 unidades cuadradas. ¿Cual es la altura y la base sabiendo que la base mide tres veces su altur
Lelu [443]

Usando el concepto del área del triángulo, se encuentra que :

  • La altura es de 16.97 unidades.
  • La base es de 50.91 unidades.

---------------------------

El área del triángulo de base b y altura h es dada por:

A = \frac{bh}{2}

---------------------------

  • El area es de <u>432 unidades quadradas</u>, o sea, A = 432
  • La base mide <u>tres veces su altura</u>, o sea, b = 3h

---------------------------

<u>Reemplazando en la ecuación para el área</u>, es posible encontrar la altura:

A = \frac{bh}{2}

432 = \frac{3h \times h}{2}

3h^2 = 864

h^2 = \frac{864}{3}

h^2 = 288

h = \sqrt{288}

h = 16.97

La altura es de 16.97 unidades.

---------------------------

La base es dada <u>en funcion da altura,</u> o sea:

b = 3h = 3(16.97) = 50.91

La base es de 50.91 unidades.

Se da un problema similar en brainly.com/question/23931350

8 0
3 years ago
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