DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
<h3>
Congruent shape</h3>
Two shapes are said to be congruent if they have the same shape, all their corresponding angles and sides are congruent to one another.
Given that DE = AB and BC = EF.
In right triangle DEF, using Pythagoras:
DF² = DE² + EF²
Also, In right triangle ABC, using Pythagoras:
AC² = AB² + BC²
But DE = AB and EF = BC, hence:
AC² = DE² + EF²
AC² = DF²
Taking square root of both sides, hence:
AC = DF
Since DE = AB, EF = BC and AC = DF, hence triangle ABC is congruent to triangle DEF.
Find out more on Congruent shape at: brainly.com/question/11329400
Volume of a cone = <span>πr^2(h/3)
r=6
h=27
v = </span><span>π(6^2)27/3
v = </span><span>π (36)(9)
v=</span><span>π324 in. cubed
or
v=1,017.36 in. cubed </span>
The answer is 240
Explanation: The Least Common Multiple (LCM) is the smallest number that two or more numbers will divide into evenly. NOTE: to find LCM you first need to know how to find GCD.
First we will find LCM for first two numbers ( 16 and24 ).
Step 1: Find the GCD (Greatest Common Divisor ) of 16 and 24 which is 8.
Step 2: Multiply the numbers 16 and 24 together ( 16 * 24 = 384 )
Step 3: Divide the 384 with 8. (384/8 = 48)
So, the LCM of 16 and 24 is 48.
Now we will find the LCM of above result (48) and third number ( 40 ) using the same procedure.
The result of this part is 240
