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SVETLANKA909090 [29]
3 years ago
14

If a math word problem has the word each do you have to multiply or Divide HELP ASAP

Mathematics
1 answer:
andrezito [222]3 years ago
5 0

Answer:

I believe its to divide

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Solve the inequality for x<br><br> 19&gt;x-5<br><br> Simplify your answer as much as possible.
Stolb23 [73]
19>x-5

Add 5 on each side giving you
19+5>x
24>x

x<24

Hope this helps!!
7 0
4 years ago
Solve the linear differential equation 2xy' + y = 2√x
77julia77 [94]

Answer:

Step-by-step explanation:

General form of the linear differential equation can be written as:

\frac{dy}{dx}+P(x)y=Q(x)

For this case, we can rewrite the equation as:

\frac{dy}{dx}+\frac{1}{2x}y=\frac{\sqrt{x}}{x}

Here P(x) =\frac{1}{2x}; Q(x)=\frac{\sqrt{x}}{x}

To find the solution (y(x)), we can use the integration factor method:

Fy(x)=\int Q(x)Fdx+C \rightarrow F=e^{\int P(x)dx

Then F=e^{\int \frac{1}{2x}dx}=e^{\frac{1}{2}\ln|x|\right}=\sqrt{|x|}

So, we can find:

y\sqrt{|x|}=\int \frac{\sqrt{x}\sqrt{|x|}}{x}dx+C

Suppose that x\in \double R, then \sqrt{|x|}=\sqrt{x} , and we find:

y\sqrt{x}=x+C \rightarrow y(x)=\sqrt{x}+\frac{C\sqrt{x}}{x}

To check our solution is right or not, put your y(x) back to the ODE:

y' = \frac{1}{2\sqrt{x}}-\frac{C}{2\sqrt{x^{3}}}

2xy'=\frac{x-C}{\sqrt{x}}

2xy'+y=\frac{x-C}{\sqrt{x}}+\sqrt{x}+\frac{C\sqrt{x}}{x}=2\sqrt{x}

(it means your solution is right)

3 0
2 years ago
Liam will spin the pointer one time what is the probability that the pointer will land on red
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Answer:

what are the other colors?

Step-by-step explanation:

one other. 50% two others 33.3% three others is 25%

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3 years ago
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Final # of pumpkins: 90
The final number of pumpkins is less than she hoped.
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3 years ago
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I did this question wrong so I had to edit it.... sorry :s.

4 0
3 years ago
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