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2 years ago

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550000000000000000 • 0.00000000044

1 answer:

nasty-shy [4]2 years ago

5 0

Answer:

550000000000000000 0.00000000044

Step-by-step explanation:

000000Oo

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How do you factor 5x^2 = 10x

denis-greek [22]

$5x^2 = 10x$

$5x^2-10x=10x-10x$

$5x^2-10x=0$

Use quadratic formula

$\quad x_{1,\:2}=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=5,\:b=-10,\:c=0:\quad x_{1,\:2}=\dfrac{-\left(-10\right)\pm \sqrt{\left(-10\right)^2-4\cdot \:5\cdot \:0}}{2\cdot \:5}$

$x=\dfrac{-\left(-10\right)+\sqrt{\left(-10\right)^2-4\cdot \:5\cdot \:0}}{2\cdot \:5}:\quad 2$

$x=\dfrac{-\left(-10\right)-\sqrt{\left(-10\right)^2-4\cdot \:5\cdot \:0}}{2\cdot \:5}:\quad 0$

$x=2,\:x=0$

8 0

3 years ago

Read 2 more answers

Stacey wishes to make a hamburger which is lower in fat without having to give up the great taste. She purchases 5 pounds of gro

STALIN [3.7K]

Answer:

%P = 8%

the percentage of fat in the mixture is 8%

Step-by-step explanation:

Given;

The percentage of fat in the mixture is;

%P = total mass of fat in mixture/total mass of mixture × 100%

%P = F/T × 100% ….....1

Mass of fat in mixture is;

She purchases 5 pounds of ground beef which is 15% fat

F1 = 15% of 5 pounds = 0.15×5 pounds

F1 = 0.75 pound

and combines it with 7 pounds of ground turkey which is only 3% fat

F2 = 3% of 7 pounds = 0.03 × 7

F2 = 0.21 pound

Total mass F = F1 + F2

F = 0.75+0.21

F = 0.96 pound

Total mass of mixture T = 5 + 7 pounds

T = 12 pounds.

From equation 1,

%P = F/T × 100%

%P = 0.96/12 × 100%

%P = 0.08×100%

%P = 8%

the percentage of fat in the mixture is 8%

5 0

3 years ago

Which of the following does NOT have a value of -5?

Contact [7]

Answer:

J. -13-18

Step-by-step explanation:

J will give the value -31

4 0

3 years ago

2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One

Stells [14]

$y'=(t+y)^2-1$

Substitute $u=t+y$ , so that $u'=y'$ , and

$u'=u^2-1$

which is separable as

$\dfrac{u'}{u^2-1}=1$

Integrate both sides with respect to $t$ . For the integral on the left, first split into partial fractions:

$\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1$

$\displaystyle\int\frac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm dt=\int\mathrm dt$

$\dfrac12(\ln|u-1|-\ln|u+1|)=t+C$

Solve for $u$ :

$\dfrac12\ln\left|\dfrac{u-1}{u+1}\right|=t+C$

$\ln\left|1-\dfrac2{u+1}\right|=2t+C$

$1-\dfrac2{u+1}=e^{2t+C}=Ce^{2t}$

$\dfrac2{u+1}=1-Ce^{2t}$

$\dfrac{u+1}2=\dfrac1{1-Ce^{2t}}$

$u=\dfrac2{1-Ce^{2t}}-1$

Replace $u$ and solve for $y$ :

$t+y=\dfrac2{1-Ce^{2t}}-1$

$y=\dfrac2{1-Ce^{2t}}-1-t$

Now use the given initial condition to solve for $C$ :

$y(3)=4\implies4=\dfrac2{1-Ce^6}-1-3\implies C=\dfrac3{4e^6}$

so that the particular solution is

$y=\dfrac2{1-\frac34e^{2t-6}}-1-t=\boxed{\dfrac8{4-3e^{2t-6}}-1-t}$

3 0

3 years ago

(01.06 MC) Jonna is 4 years older than her brother. Which of the following expressions shows the sum of their ages if b represen

Lana71 [14]

Your equation will be: b+4

6 0

3 years ago