N-8=20 is the one
probably the one cut off
Answer:
0.1111
Step-by-step explanation:
Given that you roll two dice.
the average of the high and low roll is exactly 3,
Since die can show only 1 to 6 we can say average can be 3 in each of the following case.
(1,5) (2,4) (3,3) (4,2) (5,1)
There cannot be any other combination to get average of 3.
Thus favourable events = 4
Sample space will have
(1,1)...(1,6)
(2,1)....
(6,1)...(6,6) i.e. 36
So probability that the average of the high and low roll is exactly 3
=
Answer:
Shira: x = 8
Samuel: m = 0
Step-by-step explanation:
Shira's mistake was that she subtracted 2 from both sides instead of adding to on both sides.
Correct Solving:
2x - 2 = 14
Add 2 to both sides;
2x = 16
Divide both sides by 2;
x = 8
Samuel's mistake was that when he distributed -2 to 8m and 8 he put the wrong sign for -2 * 8.
Correct Solving:
-2(8m + 8) = -16
Distribute;
-16m - 16 = -16
Add 16 to both sides;
-16m = 0
Divide both sides by -16;
m = 0
L=(8/3)W = 24 ft. Solving for W, we mult. both sides of this eqn by (3/8), obtaining
W = (3/8)(24 ft) = 9 ft (answer)
Answer:
And rounded up we have that n=421
Step-by-step explanation:
We know that the sample proportion have the following distribution:

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by
and
. And the critical value would be given by:
The margin of error for the proportion interval is given by this formula:
(a)
And on this case we have that
and we are interested in order to find the value of n, if we solve n from equation (a) we got:
(b)
We assume that a prior estimation for p would be
since we don't have any other info provided. And replacing into equation (b) the values from part a we got:
And rounded up we have that n=421