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tatiyna
3 years ago
12

How to solve this in steps?

Mathematics
2 answers:
Molodets [167]3 years ago
7 0

4a + 5 = 3(a - 7) + 2a

Start by distributing the 3 on the right side.

4a + 5 = 3 * a - 3 * 7 + 2a

4a + 5 = 3a - 21 + 2a

Now combine like terms on the right side. The like terms are 3a and 2a. They add up to 5a.

4a + 5 = 5a - 21

Subtract 5 from both sides.

4a = 5a - 26

Now subtract 5a from both sides.

-a = -26

Divide both sides by -1.

a = 26

gtnhenbr [62]3 years ago
3 0

4a + 5 = 3(a - 7) + 2a
4a + 5 = 3a - 21 + 2a
4a + 5 = 5a -21
4a -5a = -21 -5
-a = -26
a = 26

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What are the solutions of the equation. 3x-1=2x
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Answer:

there is only one solution

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x = 1

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Answer:

Step-by-step explanation:

x+y = 6

y = (6-x)

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x= 4     4 days at $7  = $28

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3 years ago
The ratio of Dawn to Mandy's savings is 6 : 7. The ratio of Mandy to Belle's savings is 2 : 3. Find the ratio of Dawn to Belle's
Mila [183]

The savings are illustrations of ratio, and the ratio of Dawn to Belle's savings in the simplest ratio is 4 : 7

<h3>How to determine the ratio?</h3>

The given ratios are:

Dawn : Mandy = 6 : 7

Mandy : Belle = 2 : 3

Multiply the second ratio by 3.5.

So, we have:

Mandy : Belle = 2 * 3.5 : 3 * 3.5

Evaluate

Mandy : Belle = 7 : 10.5

So, we have:

Dawn : Mandy = 6 : 7

Mandy : Belle = 7 : 10.5

Mandy's ratios in both equation are the same.

So, we have:

Dawn : Mandy : Belle = 6 : 7 : 10.5

Remove Mandy's ratio

Dawn : Belle = 6 : 10.5

Simplify

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Hence, the ratio of Dawn to Belle's savings is 4 : 7

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2 years ago
Find the negation of the proposition
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In accordance with <em>propositional</em> logic, <em>quantifier</em> theory and definitions of <em>simple</em> and <em>composite</em> propositions, the negation of a implication has the following equivalence:

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Herein we have a <em>composite</em> proposition, that is, the union of <em>monary</em> and <em>binary</em> operators and <em>simple</em> propositions. According to <em>propositional</em> logic and <em>quantifier</em> theory, the negation of an implication is equivalent to:

\neg (\exists \,x\, (P(x) \implies  Q(x))) \iff \forall \,x (\neg \,Q(x) \,\land \,P(x))

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8 0
1 year ago
Part 1. Please show work. Please assist me with these math problems. ​
Vitek1552 [10]

Answer: 1) 2, 3, 4, 9, 32, 279, 8896, 2481705, 22077238784

              2) 2,490,924

              3) Neither

<u>Step-by-step explanation:</u>

S_n=S_{n-2}\cdot (S_{n-1}-1)\quad \\\\S_1=2\quad given\\S_2=3\quad given\\S_3=S_1(S_2-1)\quad =2(3-1)\quad =4\\S_4=S_2(S_3-1)\quad =3(4-1)\quad =9\\S_5=S_3(S_4-1)\quad =4(9-1)\quad =32\\S_6=S_4(S_5-1)\quad =9(32-1)\quad =279\\S_7=S_5(S_6-1)\quad =32(279-1)\quad =8,896\\S_8=S_6(S_7-1)\quad =279(8896-1)\quad =2,481,705\\S_9=S_7(S_8-1)\quad =8896(2481705-1)\quad =22,077,238,784

\sum^8_{k=1}S_k\\\\=S_1+S_2+S_3+S_4+S_5+S_6+S_7+S_8\\\\= 2,490,924\\

Neither

Not arithmetic because the difference between each of the terms is not the same.            

                        S₂ - S₁          S₃ - S₂           S₄ - S₃      

                      3 - 2 = 1       4 - 3 = 1          9 - 4 = 5

Not geometric because the ratios between each of the terms is not the same.                

                       \dfrac{S_2}{S_1}=\dfrac{S_3}{S_2}\qquad \rightarrow \dfrac{3}{2}=\dfrac{4}{3}\qquad \rightarrow \text{cross multiply to get}: 9\neq 8

8 0
3 years ago
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