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jekas [21]
3 years ago
15

Need took a test with 25 questions. He lost 4 points for each of the 6 questions he got wrong and earned an additional 10 points

for answering a bonus question correctly. How many points did Ned receive overall?
Mathematics
1 answer:
Vaselesa [24]3 years ago
3 0

100 - 24 = 76

76 + 10 = 86

Ned received 86 points overall.

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Differentiate f(x) = (2x + 5)^6 with respect to x
seraphim [82]

Step-by-step explanation:

d/dx [f(x)]

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3 years ago
Find the inverse laplace transform of: (2 s + 4) / (s - 3)^3
Serhud [2]

Answer:

e^{3t}(2t+5t^{2})

Step-by-step explanation:

L^{-1}[\frac{2s+4}{(s-3)^{3}} ]=

Using the Translation theorem to transform the s-3 to s, that means multiplying by and change s to s+3

Translation theorem:L^{1} [F(s-a)=L^{-1}[F(s)|_{s \to s-a}\\ L^{1} [F(s-a)=e^{at} f(t)

L^{-1}[\frac{2s+4}{(s-3)^{3}} ]=e^{3t} L^{-1}[\frac{2(s+3)+4}{s^{3}} ]

Separate the fraction in a sum:

e^{3t} L^{-1}[\frac{2s+10}{s^{3}} ]=e^{3t} L^{-1}[\frac{2s}{s^{3}}+\frac{10}{s^{3}} ]=e^{3t} (L^{-1}[\frac{2}{s^{2}}]+ L^{-1}[\frac{10}{s^{3}}])

The formula for this is:

L^{-1}[\frac{n!}{s^{n+1}} ]=t^{n}

Modify the expression to match the formula.

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Solve

e^{3t} (2L^{-1}[\frac{1}{s^{1+1}}]+ 5 L^{-1}[\frac{2}{s^{2+1}}])=e^{3t}(2t+5t^{2} )

6 0
3 years ago
If f(x)=2^x and g(x)=2^x+4 -5 explain how the graph g(x) has been transformed from the graph of f(x) ?
nataly862011 [7]
The graph would move 4 units left and 5 down
I think
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8 0
4 years ago
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